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SCORPION-xisa [38]
3 years ago
8

Flooding on rivers is caused by human activity rather than natural events. Please select the best answer from the choices provid

ed T F
Physics
2 answers:
Olenka [21]3 years ago
5 0
False flooding rivers can be caused by weather and can also happen naturally over time.
Debora [2.8K]3 years ago
4 0

Answer:

False

Explanation:

Rivers are natural sources of water. Human is not responsible for its construction and management.

When flood comes in a river this process can not be maintained by human as they have no role in construction of it. Thus, the given statement is false.

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<span>Suppose you mixed two chemicals in the lab until you could not tell the two apart. After some time passed, a white powder formed which would not dissolve, and settled on the bottom. The mixture was first homogeneous then heterogeneous. </span>
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An automobile engine delivers 47.4 hp. how much time will it take for the engine to do 6.82 × 105 j of work? one horsepower is e
kogti [31]
1 horsepower is equal to 746 W, so the power of the engine is
P=47.4 hp \cdot 746  \frac{W}{hp}=35360 W
The power is also defined as the energy E per unit of time t:
P= \frac{E}{t}
Where the energy corresponds to the work done by the engine, which is E=6.82 \cdot 10^5 J. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
t =  \frac{E}{P}= \frac{6.82 \cdot 10^5 J}{35360 W}=19.3 s
8 0
3 years ago
9. If you placed the contents of a packet of powdered iced tea mix into a bottle of water and shook it, which of the following w
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 The water would be solvent. Its your answer!
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Name arleady three types of energy associated with a microwave
Elena L [17]
I'm pretty sure what you are trying to ask for is radiative energy, light energy, and electronic energy
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6 0
3 years ago
If one of the masses of the Atwood's machine below is 2.9 kg, what should be the other mass so that the displacement of either m
Afina-wow [57]

Answer:

2.59 Kg, 3.25 Kg

Explanation:

Acceleration can be found using equation

s=0.5at^{2} where s is the release distance, a is acceleration and t is time

Making a the subject of the formula

a=\frac {2S}{t^{2}}

Substituting 0.28 for s and time for 1 second

a=\frac {2*0.28m}{(1s)^{2}=0.56 m/s^{2}

Acceleration formula for the Atwood machine is given by

a=\frac {g(m1-m2)}{m1+m2}  where m1 and m2 are first and second masses respectively

Two situations are possible

When m1>m2

Assuming m1 is 3.7kg which is heavier than m2

Substituting a for 0.56 m/s^{2}  and m1 as 2.9Kg and taking acceleration due to gravity as 9.81 m/s^{2}  

0.56 m/s^{2}=\frac {9.81 m/s^{2}*(2.9Kg-m2)}{2.9Kg+m2}  

(0.56 m/s^{2})*(2.9Kg+m2)=9.81(2.9Kg-m2)  

(0.56 m/s^{2}+9.81)*m2=(9.81*2.9)-(2.9*0.56)  

10.37m2=28.449-1.624

10.37m2=26.825

m2=\frac {26.825}{10.37}=2.5867888138  

m2=2.59 Kg

<u>When m1<m2</u>

a=\frac {g(m2-m1)}{m1+m2}  

Then m1=2.9Kg hence

0.56 m/s^{2}=\frac {9.81(m2-2.9Kg)}{2.9Kg+m2}

(0.56 m/s^{2})*(2.9Kg+m2)=9.81 m/s^{2}*(m2-2.9Kg)

(0.56 m/s^{2}-9.81 m/s^{2})*m2=(-2.9 Kg*9.81 m/s^{2})-(2.9 Kg*0.56 m/s^{2})  

-9.25m2=-28.449-1.624=-30.073

9.25m2=30.073

m2=\frac {30.073}{9.25}=3.2511351351

m2=3.25 Kg

8 0
3 years ago
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