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2 years ago

Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0 °C.

Chemistry

1 answer:

kap26 [50]2 years ago

3 0

Answer:

Explanation:

Using the formula below to calculate the heat absorbed in each trial:

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat of water (4.184J/g°C)

∆T = change in temperature (°C)

Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0 °C.

Q = 30 × 4.184 × (40 - 0)

Q = 30 × 4.184 × 40

Q = 5,020.8J

Trial 2: Heat 40.0 grams of water at 10.0 °C to a final temperature of 40.0 °C.

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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati

babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

$MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}$

Here, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 1
Cl = 1

Number of atoms on product side are as follows.

Mn = 1
O = 1
H = 2
Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply $H_{2}O$ by 2 on product side. Therefore, the equation can be rewritten as follows.

$MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$

Hence, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Number of atoms on product side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

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2 years ago

Please help I'm not good at science

Citrus2011 [14]

Answer:

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Explanation:

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2 years ago

Would the N=O bond in HNO2 be longer, shorter, or the same length as the N-O bonds in NO2-?

aivan3 [116]

Explanation:

Bond order is inversely proportional to the bond length.

$B.O\propto \frac{1}{B.L}$

In $HNO_2$ molecule. one nitrogen is double bonded to nitrogen and one oxygen is single bonded to nitrogen and hydrogen bond.

Bond order between the (N=O) bond is 2 which means that bond length between the (N=O) bond is shorter than that of the N-O bond.
Bond order between the (N-O) bond is 1 which means that bond length of the N-O bond is longer than that of the bond length of (N=O) bond.

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2 years ago

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Which household items are usually made of metal elements?

Rus_ich [418]

a=electronic equipment and jewelry

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2 years ago

(b) What is the pH of 0.40 M triethylammonium chloride, CH₃ (CH₂)₃ NHCl ?

Valentin [98]

pH of 0.40M triethylammonium chloride is 5.90.

A solution's acidity may be determined by looking at its pH, which is a measurement of hydrogen ion concentration. Pure water slightly separates into ions with roughly equal amounts of hydrogen and hydroxyl (OH) ions. [H+] is 107 for a neutral solution, or pH = 7.

<h3>Given : </h3>

Concentration of triethylammonium chloride = 0.40M

pH = ?

<h3>Solution: </h3>

(CH3CH2)3NHCl ------> (CH3CH2)3NH⁺ + Cl⁻

(CH3CH2)3NH⁺ will react with water to give H3O⁺ .

(CH3CH2)3N will have a Kb = 5.2 x 10 ^(-4)

Kw = Kb x Ka

=> Ka = Kw / Kb = 10^(-14) / 5.2 x 10 ^(-4)

=> Ka = 1.92 x 10^(-11)

so by the reaction we have ,

Ka = x²/(0.40 - x)

=> x = 1.2393 x 10 ^(-6)

now, pH = -log( [H3O⁺]) = - log ( 1.2393 x 10 ^(-6)) = 5.906

To learn more about pH :

brainly.com/question/15289741

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