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Sergio [31]
3 years ago
9

When adding or subtracting to decimals what is the first thing you must do

Mathematics
1 answer:
Svetach [21]3 years ago
3 0
Line up the decimals 
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HELP PLEASE ASAP!!! CORRECT GETS BRAINLIEST!
ASHA 777 [7]

Answer:60

Step-by-step explanation:

5x4x3=60

6 0
3 years ago
An inequality is shown below. x + 2.5 < 20 What is the greatest value of x from the set {10.5, 12.5, 17.5, 19.5} that makes t
34kurt
C is the final answer :)
4 0
3 years ago
Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12
umka2103 [35]

Answer:

The median = 5

The mode  = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the  value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

The mode is the value which is repeated the most. = 7

Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

=7−(3*3) and 10+(3*3)

Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

6 0
3 years ago
Find the gcf of 200 and 72
Aleks04 [339]

To get the Greates Common Factor (GCF) of 72 and 200 we need to factor each value first and then we choose all the copies of factors and multiply them:

<span><span>72:   22233  </span><span>200:   222  55</span><span>GCF:   222    </span></span>

The Greatest Common Factor (GCF) is:   2 x 2 x 2 = 8

Answer: 8
3 0
3 years ago
A 6 foot tall football player casts a 16 inch shadow at the same time stadium we discussed at six for shadow how tall the bleach
katrin [286]
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.

6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.

So the bleachers are 9/2 x 6 ft = 27 ft.

For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.

So the stage will have dimensions 216 times larger than 1.75" by 3".

That would be 31ft 6ins x 54ft.

Live long and prosper.
5 0
3 years ago
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