(a) 3675 N
Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:
where
is the horizontal component of the force
m is the mass of the passenger
is the horizontal component of the acceleration
Here we have
m = 75.0 kg
Substituting,
(b) 3748 N, 11.3 degrees above horizontal
In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:
where we used
as acceleration of gravity.
So, this is the vertical component of the force exerted by the seat on the passenger:
and therefore the magnitude of the net force is
And the direction is given by
Answer:
0
Explanation:
Displacement is a vector from initial to final point. Because initial and final point are the same, so displacement is 0.
Answer: a convex lens forms a larger virtual image
Explanation: i just took the quiz
Answer:
The metabolic power for starting flight=134.8W/kg
Explanation:
We are given that
Mass of starling, m=89 g=89/1000=0.089 kg
1 kg=1000 g
Power, P=12 W
Speed, v=11 m/s
We have to find the metabolic power for starting flight.
We know that
Metabolic power for starting flight=
Using the formula
Metabolic power for starting flight=
Metabolic power for starting flight=134.8W/kg
Hence, the metabolic power for starting flight=134.8W/kg
Answer:
nine times as much.
Explanation:
K.E of A = 9 times K.E of B
