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belka [17]
3 years ago
5

Which color of light has a longer wavelength than yellow?

Physics
2 answers:
FinnZ [79.3K]3 years ago
6 0
Red has a longer wavelength than yellow
Virty [35]3 years ago
5 0
Red will be your answer
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When a system absorbs heat from its surroundings it is a(n) ____ process
Nezavi [6.7K]
C. endothermic

An endothermic process takes heat from the surroundings while an exothermic process gives out heat to the surroundings.


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3 years ago
What foods are recommended for pregnant woman?
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Answer:

Vagetagble, fruits,fresh milk and juice vitamins c

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3 years ago
A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert
pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

\theta=65.4^{\circ}

The projection of the length of the pendulum along the vertical direction is

L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

\Delta U = mg \Delta y

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta y = 0.211 m is the vertical displacement of the pendulum

So, the work done by gravity is

W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

\theta=90^{\circ}, cos \theta = 0

and so the work done is zero.

5 0
3 years ago
1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wa
love history [14]

Answer:

ans \:  = \boxed{{4.8 \times 10}^{ - 4}  Hz}

Explanation:

given \to \\  f_{r} = 350 \:  \\ v_{r} =  {3 \times 10}^{8}  \\ but \to \\ v = f \gamma   \to \:  \gamma  =  \frac{v}{f}  : hence \to \\  \gamma _{r} =  \frac{v_{r}}{f_{r}}   =  \frac{3 \times 10^{8} }{350}   =  \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\  f_{w} = water \: frequency = \:  \boxed{  ?}\:  \\ v_{w} =  14 50 \\ but \to \\ v = f \gamma   \to \:  \gamma  =  \frac{v}{f}  : hence \to \\  \gamma _{w} =  \frac{v_{w}}{f_{w}}   =  \frac{1}{100}  \times \gamma _{r}  =  \frac{1}{100}  \times 857,142.85714  \\\gamma _{w}  =  \boxed{8,571.4285714 \: m} : hence \to \:  \\ f_{w} =  \frac{v_{w}}{ \gamma _{w}}  =  \frac{1450}{8,571.4285714}  =  \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) =  \frac{f_{w}}{f_{r}}  =  \frac{0.1691666667}{350}  = 0.0004833333 \\ hence \to \\ the  \: frequency  \: of \:  the \:  radio  \: wave  \: is \to \:   \boxed{{4.8 \times 10}^{ - 4}  }\:  \\ that  \: of  \: the \:  wave  \: created  \: in  \: the  \: water.

♨Rage♨

8 0
3 years ago
A ball is thrown upwards at an unknown speed. in a time of
alexandr402 [8]

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion s=ut+\frac{1}{2} at^2, where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8m/s^2

 Substituting

    6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion v^2=u^2+2as, where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8m/s^2

    Substituting

        v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion v^2=u^2+2as, where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8m/s^2

   Substituting

     0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m

  Maximum height reached = 10.65 m

8 0
3 years ago
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