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jok3333 [9.3K]
3 years ago
13

What is 8S8 In need for a quick answer

Chemistry
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

8x8 Inc. is a provider of Voice over IP products. 8x8 products include cloud-based voice, contact center, video, mobile and unified communications for businesses.

Explanation:

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In general, ionic compounds have
Solnce55 [7]
HELLO have a nice day
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3 years ago
Which element would be most likely to lose electrons in chemical bond
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This the answer have a good day

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2 years ago
Increasing temperature can:
umka21 [38]

The answer would be A. You cannot decrease mass because of increasing temp so it can't be C and adding neutrons or protons would be changing the atom and therefore the element, and that is not possible through just an increase of temperature, so it can't be B or D. Hope this was helpful! ;)

3 0
3 years ago
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What NaCl NaCl concentration results when 249 mL 249 mL of a 0.850 M 0.850 M NaCl NaCl solution is mixed with 667 mL 667 mL of a
tamaranim1 [39]

Answer:

The answer to your question is 0.54M

Explanation:

Data

Final concentration = ?

Concentration 1 = 0.850 M

Volume 1 = 249 ml = 0.249 l

Concentration 2 = 0.420 M

Volume 2 = 0.667 M

Process

1.- Calculate the number of moles in both solutions

Number of moles 1 = Molarity 1 x Volume 1

                               = 0.850 x 0.249

                               = 0.212

Number of moles 2 = Molarity 2 x Volume 2

                                = 0.420 x 0.667

                                = 0.280

Total number of moles =  0.212 + 0.280

                                      = 0.492

2.-Calculate the final volume

Final volume = Volume 1 + Volume 2

Final volume = 0.249 + 0.667

                      = 0.916 l

3.- Calculate Molarity

Molarity = 0.492 / 0.916

Molarity = 0.54

4 0
3 years ago
Calculate the molar concentration of the polycyclic aromatic hydrocarbon (pah), anthracene (178.23 g/mol), that was found in a w
tester [92]

solution:

Calculate the molar concentration of the polycyclic aromatic hydrocarbon(PHA)(178.23g/mol),that was found in a well water sample at a concentration of 6.21ppb.Assume the density of the water is 1.00mg/mLppb corresponds to 1\mu g in 1L of sample \\the 6.21 ppb is 6.21\mu g in 1L of sample\\6.21\mu g PHA\times\frac{1mg PHA}{1000\mu g PHA}\times\frac{1g PHA}{1000\mu mg PHA}\times\frac{1mol. PHA}{178.23g PHA}\\3.48\times10^-8mol PHA\\and if we have 1L of solution\\m=\frac{moles}{v(L)}=\frac{3.48\times10^-8mol}{1L}\\3.348\times^10-8 M

3 0
3 years ago
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