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Aliun [14]
3 years ago
10

If a hypothesis can stand the test of repeated examination, it can become a _____.

Chemistry
2 answers:
Viktor [21]3 years ago
8 0
It can become a THEORY

goldenfox [79]3 years ago
3 0

Answer:

The correct answer is "theory"

Explanation:

Hello!

Let's solve this!

When a hypothesis exceeds the trial period and the sufficient amount of evidence, it can become a theory.

The correct answer is "theory"

A law is of universal application.

A theory explains why a natural phenomenon

An observation is to see something

An experiment is a test

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Referring to the article, which of the following is associated with the use of genetic engineering to clone farm
malfutka [58]

D. All of the given statements are true in context of animal cloning.

Explanation:

Cloning is the method in which a similar genetic copy is produced.

Animal cloning is a complex process in which an organism of similar type is produced with same DNA to each other.

Mostly successfully cloned animals in live are cattle,sheep,goats...

Scientists have also cloned rats,mice,rabbits,horses...

This animal cloning is used for farming by the farmers which gives acceleration in their crop production.

Animal cloning have showed some adverse affects in sheep, and other mammal animals regarding issues in their organs like liver,heart,brain etc.

The success rate is very low like 10% in animal cloning due to many reasons such as surviving from birth to the cloned animals.

8 0
3 years ago
Read 2 more answers
A gas is collected at 30 Celsius and has a pressure of 200 kPa. What pressure would it exert if the temperature changed to 40 Ce
garik1379 [7]

Answer:

206.6\ \text{kPa}

Explanation:

P_1 = Initial pressure = 200 kPa

P_2 = Final pressure

T_1 = Initial temperature = 30^{\circ}\text{C}

T_2 = Final temperature = 40^{\circ}\text{C}

We have the relation

\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\\Rightarrow P_2=\dfrac{T_2}{T_1}P_1\\\Rightarrow P_2=\dfrac{40+273.15}{30+273.15}\times 200\\\Rightarrow P_2=206.6\ \text{kPa}

The pressure that would be exerted after the temperature change is 206.6\ \text{kPa}.

6 0
3 years ago
What are some lessons from
DaniilM [7]
That if we don’t separate our selves hundreds and thousands of people will die but if we stay apart it will resolve sooner
4 0
3 years ago
Read 2 more answers
Please Help, will give 30 points! The following data was collected when a reaction was performed experimentally in the laborator
Sedaia [141]

Answer:

9 moles of NaNO3.

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaCl —> 3NaNO3 + AlCl3

Next, we shall determine the number of mole of Al(NO3)3 and NaCl that reacted and the number of mole of NaNO3 produced from the balanced equation.

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl to produce 3 moles of NaNO3.

Next, we shall determine the limiting reactant.

The limiting reactant can be obtained as follow:

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl.

Therefore, 4 moles of Al(NO3)3 will react with = (4 x 3)/1 = 12 moles of NaCl.

From the calculations made above, we can see that it will take a higher amount i.e 12 moles than what was given i.e 9 moles of NaCl to react completely with 4 moles of Al(NO3)3.

Therefore, NaCl is the limiting reactant and Al(NO3)3 is the excess reactant.

Finally, we shall determine the maximum amount of NaNO3 produced from the reaction.

In this case, the limiting reactant will be used as it will produce the maximum amount of NaNO3 since all of it is consumed by the reaction.

The limit reactant is NaCl and the maximum amount of NaNO3 produced can be obtained as follow:

From the balanced equation above,

3 moles of NaCl reacted to produce 3 moles of NaNO3.

Therefore, 9 moles of NaCl will also react to produce 9 moles of NaNO3.

From the calculations made above, the maximum amount of NaNO3 produced is 9 moles

6 0
3 years ago
How many moles of ammonia gas occupy 50 mL at at 700 kPa and 30.0 0C?
nalin [4]

For the conversions

I will start with pressure
1atm=101.3kPa
x =700kPa
x=700kPa/101.3kPa
x=6.91atm

Temperature
273K+30.00C
303K

Volume
1L=1000ml
x =50ml
x=0.05L

PV=nRT
6.91*0.05=n*0.08206*303
0.3455=24.86418n
0.3455/24.86418=n
0.0138=n
number of moles = 0.0138moles

Note: 0.08206 is the gas constant in this case
6 0
3 years ago
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