O2 + C3H60 → H2O + CO2 Balance please
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Answer:
The enthalpy change during the reaction is -7020.09 kJ/mole.
Explanation:
First we have to calculate the heat gained by the calorimeter.
where,
q = heat gained = ?
c = specific heat =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
The heat gained by water present in calorimeter. = q'
where,
q' = heat gained = ?
m = mass of water =
c' = specific heat of water =
= final temperature =
= initial temperature =
q ' = 12,060.38 J
Now we have to calculate the enthalpy change during the reaction.
where,
= enthalpy change = ?
Q = heat gained = -(q+q') = -(2,485.25 J + 12,060.38 J)= -14,545.63 J
Q = -14.54563 kJ
n = number of moles fructose =
Therefore, the enthalpy change during the reaction is -7020.09 kJ/mole.