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4 years ago

A spy in a speed boat is being chased down a

1 answer:

8 0

V1 =16 m/s and V2 =24 m/s. Constant acceleration = 9.8 m/s. The range for a horizontal drop is R=V1* the square root(2h/g. R1=16 * the square root of 2*5.4/9.8. =16.796 meters. And R2= 24 * the square root of 2*5.4/9.8 = 25.194. R2 - R1 = how far apart the two vessel will be. 25.194 - 16.796 = 8.398 or 8.4 meters

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A plane takes off in san francisco at noon and flies toward the southeast. an hour later, it is 400 kilometers east and 300 kilo

eduard

This first step involves a right triangle. If the plane is 400 km east and 300 km south of the origin, and it flew in a straight line, then you can construct a right triangle with side lengths 300, 400, and c. You may recognize that these are multiples of the Pythagorean triple 3, 4, 5, so the side length c is 500 km. Otherwise, you would write
$c^2 = 300^2+400^2 \\ c = 500$ .

This second step is, if I am correctly interpreting "degrees south of east," to find the angle formed by the horizontal line representing the east and the path of the plane. I made a diagram that does just that (see attached). You can use a trig function of one of the angles to solve. I chose
$tan(C)= \frac{3}{4} \\ arctan( \frac{3}{4})=36.870$ . Thus, I believe it is 37° south of east.

5 0

3 years ago

A 2000 kg car moving at 100 km/h crosses the top of a hill with a radius of curvature of 100 m. What is the normal force exerted

Tpy6a [65]

Answer:

The normal force the seat exerted on the driver is 125 N.

Explanation:

Given;

mass of the car, m = 2000 kg

speed of the car, u = 100 km/h = 27.78 m/s

radius of curvature of the hill, r = 100 m

mass of the driver, = 60 kg

The centripetal force of the driver at top of the hill is given as;

$F_c = F_g - F_N$

where;

Fc is the centripetal force

$F_g$ is downward force due to weight of the driver

$F_N$ is upward or normal force on the drive

$F_N = F_g-F_c\\\\F_N = mg - \frac{mv^2}{r} \\\\F_N = (60 \times 9.8) -\frac{60 \ \times \ 27.78^2 \ }{100} \\\\F_N = 588 \ N - 463 \ N\\\\F_N = 125 \ N$

Therefore, the normal force the seat exerted on the driver is 125 N.

6 0

3 years ago

State and apply the relation between electric force and electric field.

Olin [163]

Answer:

The following is the relation between electric force and field

$Electric Field = Electric Force / charge$

Explanation:

Electric force is the magnitude of electrostatic forces between two charges which is directly proportional to product of both charges and inversely proportional to the square of the distance between them.

$F=k*q1*q2/r^2$

Here k is the coulumb's constant.

Where as the electric field is the electric force per unit charge. It is the function of electric force. It is the vector quantity and its direction is taken radially inward or outward depending on the nature of charge.

Its equation is

Electric Field $E=F/q$

Electric Field units are in volts where as Electric force units are newtons.

5 0

4 years ago

Alice kicks a soccer ball with a mass of 2 kg. The ball leaves the ground moving 30 meters per second. What is the kinetic energ

sleet_krkn [62]

By using the formula:

• K.E = ½mv²

mass, m = 2 kg
Velocity, v = 30 m/s

→ K.E = ½ × 2 × (30)² J

→ K.E = (30)² J

→ K.E = 900 J (Answer)

5 0

2 years ago

A soccor ball lies still on the grass until it is kicked by a player. This desribes which of Newton's Laws?

stira [4]

It describes the third one. when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

8 0

3 years ago