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elena-14-01-66 [18.8K]
2 years ago
8

A 2000 kg car moving at 100 km/h crosses the top of a hill with a radius of curvature of 100 m. What is the normal force exerted

by the seat on the driver if the mass of the driver is 60 kg?
Physics
1 answer:
Tpy6a [65]2 years ago
6 0

Answer:

The normal force the seat exerted on the driver is 125 N.

Explanation:

Given;

mass of the car, m = 2000 kg

speed of the car, u = 100 km/h = 27.78 m/s

radius of curvature of the hill, r = 100 m

mass of the driver, = 60 kg

The centripetal force of the driver at top of the hill is given as;

F_c = F_g - F_N

where;

Fc is the centripetal force

F_g is downward force due to weight of the driver

F_N is upward or normal force on the drive

F_N = F_g-F_c\\\\F_N = mg - \frac{mv^2}{r} \\\\F_N = (60 \times 9.8) -\frac{60 \ \times \ 27.78^2 \ }{100} \\\\F_N = 588 \ N - 463 \ N\\\\F_N = 125 \ N

Therefore, the normal force the seat exerted on the driver is 125 N.

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