Sodium. 11
Carbon. 12
Hydrogen 1
Oxygen 2
Fluuorine. 14
Boron. 5
Lithium. 6
Helium 3
Phosphorus 15
Sulfur 6
Answer:
The degree of dissociation of acetic acid is 0.08448.
The pH of the solution is 3.72.
Explanation:
The ![pK_a=4.756](https://tex.z-dn.net/?f=pK_a%3D4.756)
The value of the dissociation constant = ![K_a](https://tex.z-dn.net/?f=K_a)
![pK_a=-\log[K_a]](https://tex.z-dn.net/?f=pK_a%3D-%5Clog%5BK_a%5D)
![K_a=10^{-4.756}=1.754\times 10^{-5}](https://tex.z-dn.net/?f=K_a%3D10%5E%7B-4.756%7D%3D1.754%5Ctimes%2010%5E%7B-5%7D)
Initial concentration of the acetic acid = [HAc] =c = 0.00225
Degree of dissociation = α
![HAc\rightleftharpoons H^++Ac^-](https://tex.z-dn.net/?f=HAc%5Crightleftharpoons%20H%5E%2B%2BAc%5E-)
Initially
c
At equilibrium ;
(c-cα) cα cα
The expression of dissociation constant is given as:
![K_a=\frac{[H^+][Ac^-]}{[HAc]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BAc%5E-%5D%7D%7B%5BHAc%5D%7D)
![1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}](https://tex.z-dn.net/?f=1.754%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7Bc%5Ctimes%20%5Calpha%20%5Ctimes%20c%5Ctimes%20%5Calpha%7D%7B%28c-c%5Calpha%29%7D)
![1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}](https://tex.z-dn.net/?f=1.754%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7Bc%5Calpha%20%5E2%7D%7B%281-%5Calpha%29%7D)
![1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}](https://tex.z-dn.net/?f=1.754%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B0.00225%20%5Calpha%20%5E2%7D%7B%281-%5Calpha%29%7D)
Solving for α:
α = 0.08448
The degree of dissociation of acetic acid is 0.08448.
![[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Calpha%20%3D%200.00225M%5Ctimes%200.08448%3D0.0001901%20M)
The pH of the solution ;
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
![=-\log[0.0001901 M]=3.72](https://tex.z-dn.net/?f=%3D-%5Clog%5B0.0001901%20M%5D%3D3.72)
<u>Answer:</u> The chemical reaction for the synthesis reaction is given below.
<u>Explanation:</u>
Synthesis reaction is defined as a chemical reaction in which two small chemical substances combine together to form a single compound. The general equation for this chemical reaction follows:
![A+B\rightarrow AB](https://tex.z-dn.net/?f=A%2BB%5Crightarrow%20AB)
For the reaction of calcium and oxygen combining together to form calcium oxide, the equation follows:
![2Ca(s)+O_2(g)\rightarrow 2CaO(s)](https://tex.z-dn.net/?f=2Ca%28s%29%2BO_2%28g%29%5Crightarrow%202CaO%28s%29)
By Stoichiometry,
2 moles of calcium element combines together with 1 mole of oxygen gas to produce 2 moles of calcium oxide.
Hence, the chemical equation for the reaction is given above.
Volume percent<span> or </span>volume/volume percent<span> (v/v%) is used when preparing solutions of liquids. It will have units of volume of the smaller composition substance over the volume of the solution. We calculate as follows:
12.5 mL ethanol = .225 mL ethanol / 1 mL solution ( V )
V = 55.56 mL of the 22.5 % by volume ethanol solution is needed
Hope this answers the question.</span>