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Luden [163]
3 years ago
9

A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the v

ertical. Insuch a condition of static equilibrium, what is the magnitude of the horizontal force being applied by the partner? The weight of the artist is 7.61 10 N
Physics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

F_t=371.16N

Explanation:

The weight 7.61x10^2N

The angle 26.0

To determine the magnitude of horizontal force applied

tan(\alpha)=\frac{F_t}{F}

F_t=F*tan(\alpha)

F_t=7.61x10^2N*tan(26.0)

F_t=371.16N

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How many days sun rises in a year​
Lana71 [14]

Answer:

365

Explanation:

there are 365 days in a year

8 0
3 years ago
A speeding motorist traveling down a straight highway at 100 km/h passes a parked police car. It takes the police constable 1.0
Lubov Fominskaja [6]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

<u>t = 7.5 s</u>

6 0
3 years ago
Sprinters push off from the ball of their foot, then bend their knee to bring their foot up close to the body as they swing thei
Nataliya [291]

There are two interchangeable concepts that can be applied to this theory. The first one is the moment of Inertia and the second the perioricity. When the runners put their leg forward they reduce their moment of inertia allowing their center of mass to maintain the speed they carry and not waste energy. In this way when they swing, the leg begins to act as a kind of pendulum, and remember that the pendulum is directly proportional to the length, that is,

T = 2 \pi \sqrt {l / g}

In this way, by bringing their legs closer they reduce the distance and make the period shorter.

7 0
3 years ago
An iron anchor of density 7810.00 kg/m^3 appears 252 N lighter in water than in air. (a) What is the volume of the anchor?(b) Ho
RSB [31]

Answer:

(a)The volume of the iron anchor = 25.2 m³

<em>(b)The mass of iron = 196812 kg</em>

Explanation:

<em>Density:</em> This is the ratio of the mass of a body to its volume. The S.I unit of density is <em>kg/m³</em>

(a)

From Archimedes principle, the iron will displace a volume of water that is equal to its volume. And the weight of water displaced is equal to loss in weight or upthrust.

Therefore, Upthrust = lost in weight = weight of water displace.

Therefore, Volume of the iron = mass of water displace/density of water

Vi = m₁/D₁........................... Equation 1

Where Vi = volume of iron, m₁ = mass of water displaced, D₁ = Density of water.

<em>Given: upthrust = 252 N, ∴ m₁ = 252/10 = 25.2 kg.</em>

<em>Constant: D₁ = 1.0 kg/m³</em>

<em>Substituting these values into equation 1,</em>

Vi = 25.2/1.0

Vi = 25.2 m³

Therefore the volume of the iron anchor = 25.2 m³

(b)

<em>Density of the iron = mass of the iron/volume of the iron.</em>

<em>Therefore, Mass of the iron = Density of the iron × volume of the iron...........................................equation 2</em>

<em>Given: Density of the iron = 7810 kg/m³, Volume of the iron =  25.2 m³</em>

<em>Substituting these values into equation 2,</em>

<em>Mass of the iron = 7810×25.2</em>

<em>Mass of the iron  = 196812 kg.</em>

<em>Therefore the mass of iron = 196812 kg</em>

8 0
3 years ago
Choose the TRUE statement about momentum. A. An object can never actually have zero momentum. B. An object with a large mass alw
ra1l [238]
The answer is d. momentum can be transferred from one object to another object
5 0
3 years ago
Read 2 more answers
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