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Luden [163]
3 years ago
9

A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the v

ertical. Insuch a condition of static equilibrium, what is the magnitude of the horizontal force being applied by the partner? The weight of the artist is 7.61 10 N
Physics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

F_t=371.16N

Explanation:

The weight 7.61x10^2N

The angle 26.0

To determine the magnitude of horizontal force applied

tan(\alpha)=\frac{F_t}{F}

F_t=F*tan(\alpha)

F_t=7.61x10^2N*tan(26.0)

F_t=371.16N

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siniylev [52]

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5 0
3 years ago
Two bodies made of the same material have same external dimension and appearance, but one is compact solid and other is hollow.
Bumek [7]

Answer:

Different

Explanation:

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5 0
3 years ago
What is the value of acceleration due to gravity at the pole, equator and the centre of the earth
fgiga [73]

Answer:

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.

7 0
2 years ago
Using monochromatic light of 410 nm wavelength, a single thin slit forms a diffraction pattern, with the first minimum at an ang
VLD [36.1K]

Answer:

c. 307 nm

Explanation:

angular position of first dark fringe =  λ / d ,   λ is wavelength and  d is width of slit .

(40 x π ) / 180 = 410 / d

angular position of second  dark fringe =  2 x λ / d ,   λ is wavelength and  d is width of slit .

(60 x π ) / 180 = 2 x λ / d

Dividing these equations

60 / 40 =  2 x λ / 410

λ = 307.5 nm.

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4 years ago
What happens when a light ray is parallel to the principal axis ?
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Answer:

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Hope this helps...

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