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Luden [163]
3 years ago
9

A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the v

ertical. Insuch a condition of static equilibrium, what is the magnitude of the horizontal force being applied by the partner? The weight of the artist is 7.61 10 N
Physics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

F_t=371.16N

Explanation:

The weight 7.61x10^2N

The angle 26.0

To determine the magnitude of horizontal force applied

tan(\alpha)=\frac{F_t}{F}

F_t=F*tan(\alpha)

F_t=7.61x10^2N*tan(26.0)

F_t=371.16N

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Part B)

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