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Luden [163]
3 years ago
9

A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the v

ertical. Insuch a condition of static equilibrium, what is the magnitude of the horizontal force being applied by the partner? The weight of the artist is 7.61 10 N
Physics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

F_t=371.16N

Explanation:

The weight 7.61x10^2N

The angle 26.0

To determine the magnitude of horizontal force applied

tan(\alpha)=\frac{F_t}{F}

F_t=F*tan(\alpha)

F_t=7.61x10^2N*tan(26.0)

F_t=371.16N

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Answer:

c = 1163.34 J/kg.°C

Explanation:

Specific heat capacity:

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Use this equation:

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Rearranging the equation to find the specific heat (c) you get this:

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c = (( 0.285 (4186) + (0.15)(900)) (32 -25.1)) / ((0.125) (95 - 32))

c = 1163.34 J/kg.°C

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The correct answer would be odor. Because it's sweet.  Boiling shape and hardness have nothing to do with sweet and floral :)

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Which of the following best describes the term thermal energy? Choose one: A. The energy of an object in motion due to its mass
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Answer:

The correct option is (d).

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Answer:

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Explanation:

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We can also rewrite it as

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So if we want to make the force F twice as strong,

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