<u><em>About 1,199 </em></u><span><u><em>miles From Burma To North.</em></u></span>
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.
</span>
Answer:
Option(a) All of the above;
Explanation:
In relation to physics, force can be defined as any interaction between two bodies or objects that will change their motion. In simpler terms force refers to push/pull of a body with mass m that results in change of velocity or the acceleration a.
The concept of force can be better studied with the help of Newton’s three laws of motion. In it, he explained the nature of action of forces under normal condition
When vapor pressure equals atmospheric pressure, it's called boiling point of that liquid.
Answer:
Both vehicles experience the same change in momentum
Explanation:
Let m represent the mass of the vehicle, and 2m represent the mass of the large truck, and let v represent their initial speed, we have;
The total initial momentum,
given as follows;
= 2·m·v - m·v = m·v
The total final momentum,
= (2·m + m) × 
By the principle of conservation of linear momentum, the total initial momentum = The total final momentum
m·v = (2·m + m) × 
m·v = 3·m·
∴ v = 3 × 
= v/3
The change in the momentum for the large truck = 2·m·v - 2·m·
Therefore;
The change in the momentum for the large truck = 2·m·v - 2·m·v/3 = 2·m·(v - v/3)
The change in the momentum for the large truck = 2·m·(v - v/3) = 2·m·2·v/3 = 4·m·v/3
The change in the momentum for the car = m·v - m·(-
) = m·v - m·(-v)/3 = m·v + m·(v)/3 = 4·m·v/3
Therefore, the change in the momentum for the large truck = The change in the momentum for the car and both vehicles experience the same change in momentum.