It's by number of protons
B. a sound wave that he could just barely hear
When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.
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A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity
and radius from the center of the disc = 300 mm
Answer:
the angular acceleration = 205.706 rad/sec²
Explanation:
GIVEN THAT:
The disc mass = 8 kg
Force = 
We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

Also;
the initial angular velocity
radius from the center of the disc = 300 mm = 0.3 m
Thus; the mass moment about the Inertia can be determined via the following expression;



Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;
SO:






Hence; the angular acceleration = 205.706 rad/sec²
Answer:
See explanations below
Explanation:
1) KE = 1/2mv²
mass m = 0.142kg
v = 40m/s
KE = 1/2 * 0.142 * 40^2
KE = 1/2 * 0.142 * 1600
KE = 800*0.142
KE = 113.6Joules
2) KE = 1/mv^2
KE = 196
mass m = ?
velocity v = 52m/s
Substitute
196 = 1/2*m*52²
196 = 1352m
m = 196/1352
m = 0.145kg
Hence the mass of the baseball is 0.145kg
3) KE = 1/2mV^2
288 = 1/2 * 4v²
288 = 2v²\
v² = 288/2
v² = 144
v = 12m/s
The velocity of the shotput is 12m/s