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Volgvan
3 years ago
12

The formula for sulfuric acid is h2so4. how many elements does it contain

Physics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

Sulfuric Acid, H2SO4 is a chemical compound made up of two hydrogen atom, one sulfer atom, and four oxygen atoms.

Explanation:

prisoha [69]3 years ago
3 0

It contains 2 hydrogens (H2), 1 Sulphur (S) AND 4 Oxygens (O4)

Please mark Brainliest! :)

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7 0
3 years ago
A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to t
Soloha48 [4]

A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity \omega _o = 1 \ rad/s and radius from the center of the disc = 300 mm

Answer:

the angular acceleration = 205.706 rad/sec²

Explanation:

GIVEN THAT:

The disc mass = 8 kg

Force = \dfrac{1}{4} \ \ \theta ^2* N

We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

\theta = 5 rev * (\dfrac{2 \  \pi  * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad

Also;

the initial angular velocity \omega _o = 1 \ rad/s

radius from the center of the disc = 300 mm = 0.3 m

Thus; the mass moment about the Inertia can be determined via the following expression;

I_o = \dfrac{1}{2}*m*r^2

I_o = \dfrac{1}{2}*8*0.3^2

I_o = 0.36 \ kg/m^3

Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;

SO:

\sum M_o = I_o \alpha

F*0.3 = 0.36* \alpha

\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha

\alpha = 0.20836 \  \theta^2 \ rad/sec^2

\alpha = 0.20836 \  (10 \ \pi )^2 \ rad/sec^2

\alpha = 205.706 \ rad/sec^2

Hence; the angular acceleration = 205.706 rad/sec²

6 0
3 years ago
1. A baseball that has been thrown is travelling at 40m/s. If
nignag [31]

Answer:

See explanations below

Explanation:

1) KE = 1/2mv²

mass m = 0.142kg

v = 40m/s

KE = 1/2 * 0.142 * 40^2

KE = 1/2 * 0.142 * 1600

KE = 800*0.142

KE = 113.6Joules

2) KE = 1/mv^2

KE = 196

mass m = ?

velocity v = 52m/s

Substitute

196 = 1/2*m*52²

196 = 1352m

m = 196/1352

m = 0.145kg

Hence the mass of the baseball is 0.145kg

3) KE = 1/2mV^2

288 = 1/2 * 4v²

288 = 2v²\

v² = 288/2

v² = 144

v = 12m/s

The velocity of the shotput is 12m/s

4 0
3 years ago
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