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Volgvan
2 years ago
12

The formula for sulfuric acid is h2so4. how many elements does it contain

Physics
2 answers:
kifflom [539]2 years ago
8 0

Answer:

Sulfuric Acid, H2SO4 is a chemical compound made up of two hydrogen atom, one sulfer atom, and four oxygen atoms.

Explanation:

prisoha [69]2 years ago
3 0

It contains 2 hydrogens (H2), 1 Sulphur (S) AND 4 Oxygens (O4)

Please mark Brainliest! :)

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So Neon ( Ne) is the correct answer.

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Why do you think the standards changed over time?
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Which type of nuclear reaction involves combining light elements into a heavier element, with a resultant release of great amoun
torisob [31]

Answer: Fusion

Explanation:

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Nuclear fission is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

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3 years ago
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A ball is thrown straight up with enough speed so that it is in the air for several seconds. Assume the positive direction is up
Andrew [12]

Answer:

a) v= 0 m/s b) v= 6.86 m/s

Explanation:

a) When the ball reaches to its highest point, under the influence of gravity, before starting to fall down, it momentarily comes to an stop (this is needed prior to change direction in any movement), so, applying the definition of acceleration, and replacing the acceleration a by g, we have:

vf = v₀ - g*t (1)

The minus sign means that the acceleration due to gravity is always downward, so if we assume that the positive direction is upwards it must be negative.

At the highest point, vf= 0.

b) Prior to solve this point, we need to know which is the time when the ball reaches to its highest point.

As we know vf=0, we can solve (1) for t, as follows:

th = v₀/g

Now, for a time that is 0.7 s before this time, applying the acceleration definition and solving for v again, we have:

v = v₀ -(g *(th-0.7 s)), but th= v₀/g, so we get:

v= v₀ -g((v₀/g)-0.7 s) = v₀ - v₀ + g*0.7 s

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⇒ v = 6.86 m/s

6 0
3 years ago
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel
mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

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\vec v_{ra} = 12\hat j

also it is given that speed of air is 6.7 m/s relative to ground

\vec v_a = 6.7 \hat i

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now by rearranging the terms

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now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

v_r = \sqrt{12^2 + 6.7^2}

v_r = 13.7 m/s

so the net speed of Robin with respect to ground will be 13.7 m/s

7 0
3 years ago
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