Start with the conservation of energy. The spring potential energy and the mass' kinetic energy will fluctuate over time, but their sum will stay constant. The maximum spring potential energy equals the maximum kinetic energy.
0.5mv² = 0.5kx²
m is the mass, v is the maximum velocity, k is the spring constant, and x is the maximum displacement along the spring.
Given values:
m = 4.1kg
v = 0.78m/s
Calculate the maximum kinetic energy.
Max KE = 0.5mv² = 1.247J
Set this equal to the maximum spring potential energy.
Max spring PE = 0.5kx² = 1.247J
<em>x² = 2.494/k</em>
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The spring force is F = kx
Max F = kx = 13N
x = 13/k
<em>x² = 169/k²</em>
Set both values of x² equal to each other and solve for k the spring constant:
2.494/k = 169/k²
2.494k = 169
k = 67.8N/m
Use k to find x:
Max F = kx = 13N
67.8x = 13
x = 0.192m
The frequency of the system is given by:
f = (1/(2π))√(k/m)
f is the frequency, k is the spring constant, m is the mass.
f = (1/(2π))√(67.8/4.1)
f = 0.647Hz
