Answer:
The gravitational potential energy of that rock is 174371.4 J.
Explanation:
Given
To determine
We need to find the gravitational potential energy of the rock
We know that the potential energy of a body is termed as the stored energy due to its position.
One kind of energy comes from Earth's gravity — Gravitational potential energy (GPE).
Gravitational potential energy (GPE) can be determined using the formula
where
is the mass
is the gravitational acceleration which is equal to g = 9.8 m/s²
is the height
- GPE is the Gravitational potential energy
now substituting m = 59.31, h = 300 and g = 9.8
J
Therefore, the gravitational potential energy of that rock is 174371.4 J.
Answer:
Explanation:
wavelength 
d = 0.190 mm = 0.190 × 10⁻³ m
D = 1.91 m
By using the formula:
The first maximum will appear at an angle from the beam axis
Yes. The line is increasing. The flat line at the top of the graph is where there is not acceleration and the decreasing line is deceleration.
Answer:
Vdc=10V
Explanation:
in a closed loop consisting of a super charged capacitor and an inductor, the super charge capacitor acts as a supply when the loop is closed, at t=0, the emf stored in the capacitor is 10V (q/c); and at that same time Vl= voltage across the inductor or loop too would be 10V,
if the loop remains closed for a longer period, the inductor would absorb energy from the capacitor till it dissipates all charges with itself.
