Idk 0? I thought when an object is at potential energy it at its lowest point. Sorry guess this doesn't help If I just had the lesson I may be able 2 help.
Answer:
239.7 g
Explanation:
Step 1: Write the balanced equation
2 LiBr + I₂ → 2 LiI + Br₂
Step 2: Convert the molecules of iodine to moles
We have 9.033 × 10²³ particles (molecules) of iodine. In order to convert molecules to moles, we will use the <em>Avogadro's number</em>: there are 6.022 × 10²³ molecules of iodine in 1 mole of iodine.

Step 3: Calculate the moles of bromine produced
The <em>molar ratio of I₂ to Br₂</em> is 1:1. Then, the moles of bromine produced are 1.500 moles.
Step 4: Calculate the mass of bromine
The <em>molar mass of bromine</em> is 159.81 g/mol. The mass corresponding to 1.500 moles is:

Answer:
Dalton's atomic theory consisted of several postulates.
Explanation:
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All matter consists of indivisible particles called atoms.
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Atoms of the same element are similar in shape and mass, but differ from the atoms of other elements.
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Atoms cannot be created or destroyed.
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Atoms of different elements may combine with each other in a fixed, simple, whole number ratio to form compound atoms.
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Atoms of same element can combine in more than one ratio to form two or more compounds.
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Atoms are the smallest unit of matter that can take part in a chemical reaction.
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Answer:
33 moles
Explanation:
The given chemical reaction is 2C₄H₁₀(g) + 13 O₂(g) → 10H₂O(g) + 8CO₂(g)
The number of moles of each reactant are as follows;
Butane, C₄H₁₀ = 2 moles of (g) + 13 (g) → 10H₂O(g) + 8CO₂(g)
Oxygen gas, O₂ = 13 moles
Water, H₂O = 10 moles
Carbon dioxide, CO₂ = 8 moles
The total number of moles, n = (2 + 13 + 10 + 8) = 33
∴ The total number of moles involved in the reaction, n = 33 moles.
Hexane and 2-methylpentane. If you draw the structures out, you can see that both isomers have 6 carbon atoms and 14 hydrogen atoms. Hence they have the same molecular formula but a different structural formula. I suggest drawing the compounds out for these types of questions to visualise it.