1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alekssandra [29.7K]
3 years ago
5

1 draw the 1st 20 Element

Chemistry
1 answer:
Artemon [7]3 years ago
5 0
cation means the primation in the air
You might be interested in
The accepted value for the molar volume of a gas is 22.4 L. Sarah's experimental data indicated that a mole of a gas had a volum
Amanda [17]

Answer:

Percent error = 12.5%

Explanation:

In a measurement you can find percent error following the formula:

Percent error = |Measured value - Accepted Value| / Acepted value * 100

Based on the data of the problem, accepted value is 22.4L and the measured Value (Value of Sara) was 19.6L.

Replacing:

Percent error = |Measured value - Accepted Value| / Acepted value * 100

Percent error = |19.6L - 22.4L| / 22.4L * 100

Percent error = |-2.8L| / 22.4L * 100

Percent error = 2.8L / 22.4L * 100

Percent error = 12.5%

3 0
3 years ago
1. Given below are the figures showing particles of a matter in its three
stepan [7]

Answer:the answer is c

Explanation:

6 0
3 years ago
Which of the following contribute(s) to most of the mass of an atom?
xenn [34]

Answer:

1.

B) protons and newtrons

2.

D)

3.

C)

4.

A)

6 0
3 years ago
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
Please help..... who is up for a zoom to help me with balancing equations ​
Alex787 [66]

Answer:

Um I can help but not on zo.om. I can help u on here just post ur question and I will answer it

8 0
3 years ago
Read 2 more answers
Other questions:
  • The density of aluminum is 2.70 g/cm3. Apiece of aluminum foil that is 1000 cm on each side has a mass of 440. mg. How thick is
    6·1 answer
  • What fraction of the earth did the former continental glaciers cover?
    11·2 answers
  • What is the molar solubility of magnesium carbonate ( MgCO3 ) in water? The solubility-product constant for MgCO3 is 3.5 × 10-8
    15·2 answers
  • What type of graphic image is shown in Image 12
    8·1 answer
  • What will the pressure of the gas be if the temperature rises to 87°C?
    12·1 answer
  • HELP ASP
    8·1 answer
  • Please help asap! Giving brainliest to correct answer.
    15·1 answer
  • How many carbon (C) atoms are in CaCO3?​
    6·2 answers
  • _ _ _+Cl₂ ➡️ MgCl₂ Complete given Reaction<br>​
    12·2 answers
  • Question 54
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!