Answer:
P₂ = 394.4 KPa
Explanation:
Given data:
Volume of gas = 152 dm³
Pressure of gas = 98.6 KPa
Final pressure = ?
Final volume = quartered = 1/4×152 = 38 dm³
Solution:
P₁V₁ = P₂V₂
P₂ = P₁V₁/V₂
P₂ = 98.6 KPa . 152 dm³ / 38 dm³
P₂ = 14987.2 KPa. dm³ / 38 dm³
P₂ = 394.4 KPa
An electron is found whizzing around the nucleus, so in subatomic particles.
Alkenes must undergo addition because they have easily broken tt bonds.
Markonikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.
alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.
Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.
In hydroboration, the boron atom bonds to the substituted carbon.
Hydroxides, amines and alcoxides undergo substitution and elimination, but can do so only when the heteroatom is made into a good leaving group.
Answer: 670K
Explanation:
Given that,
Original volume of gas V1 = 1.22 L
Original temperature T1 = 286 K
New volume V2 = 2.86 L
New temperature T2 = ?
Since volume and temperature are involved while pressure is constant, apply the formula for Charles law
V1/T1 = V2/T2
1.22 L/286 K = 2.86 L/ T2
Cross multiply
1.22 L x T2 = 286 K x 2.86 L
1.22T2 = 817.96
Divide both sides by 1.22
1.22T2/1.22 = 817.96/1.22
T2 = 670.459 K (Round to the nearest whole number as 670 K)
Thus, the temperature of the gas is 670 Kelvin
Substances that cannot be separated and found on a periodic table are elements.
