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elena-s [515]
3 years ago
8

What is the formula for vanadium oxide

Chemistry
2 answers:
Korvikt [17]3 years ago
8 0

Vanadium(V) oxide is the inorganic compound with the formula V₂O₅. Commonly known as vanadium pentoxide, it is a brown/yellow solid, although when freshly precipitated from aqueous solution, its colour is deep orange. Because of its high oxidation state, it is both an amphoteric oxide and an oxidizing agent.

formula:V2O5

pls mark as brainliest

coldgirl [10]3 years ago
3 0

Answer:

is it vanadium v oxide or just vanadium oxide

Explanation:

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HELP PLEASE
7nadin3 [17]

Answer:

0.031moles

Explanation:

ok so it would help if I knew the marks but 1 mole = 1000L so if the volume was 31L then if you convert you will get that answer

8 0
3 years ago
The relative atomic mass of aluminium is 27 and of oxygen is 16. The aluminium ore shown below contains 5.4kg of aluminium and 4
sesenic [268]
<span><span>Calculate the % of copper in copper sulphate, 
CuSO4 </span> Relative atomic masses: Cu = 27, S = 16 and O = 25.92
relative formula mass = 27 + 16 + (5.4x4.8) = 286.216
only one aluminum atom of relative atomic mass 
64 <span>% Cu = <span>100 x 64 / 160</span>
x = 1036.8
</span></span>
6 0
3 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-Q_1=Q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

5 0
4 years ago
Using this equation, m1v2=m2v2 , calculate the diluted molarity of 100 mL of a 0.5 M solution when 50 mL of
geniusboy [140]

The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

<h3>Molarity of diluted solution (M₂) =? </h3>

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

<h3>M₁V₁ = M₂V₂</h3>

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

<h3>M₂ = 0.33 M</h3>

Therefore, the molarity of the diluted solution is 0.33 M

Learn more: brainly.com/question/24625656

8 0
3 years ago
At room temperature, all samples of liquid water must have the same
laiz [17]
Density. water's density is always 1 g/ cm^3
4 0
3 years ago
Read 2 more answers
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