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sweet-ann [11.9K]
2 years ago
12

If I have 0.275 moles of gas at a temperature of 75 K and a pressure of 1530 mmHg, what is the volume of the gas?

Chemistry
1 answer:
Maru [420]2 years ago
6 0

Answer: The volume of the gas is 0.84 Liters

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1530 mm Hg = 2.01 atm     (760mmHg=1atm)

V = Volume of gas = ?

n = number of moles = 0.275

R = gas constant =0.0821Latm/Kmol

T =temperature =75K

V=\frac{nRT}{P}

V=\frac{0.275atm\times 0.0820 Latm/K mol\times 75K}{2.01atm}=0.84L

Thus the volume of the gas is 0.84 Liters

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Answer:

<em>293.99 g </em>

OR

<em>0.293 Kg</em>

Explanation:

Given data:

Lattice energy of Potassium nitrate (KNO3) = -163.8 kcal/mol

Heat of hydration of KNO3 = -155.5 kcal/mol

Heat to absorb by KNO3 = 101kJ

To find:

Mass of KNO3 to dissolve in water = ?

Solution:

Heat of solution = Hydration energy - Lattice energy

                           = -155.5 -(-163.8)

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We already know,

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Therefore,

= 4.184 kJ/mol x 8.3 kcal/mol

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Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved in water.

For 101 kJ of heat would be

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Mass of KNO3 = Molar mass x moles

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                         = 293.99 g

                         = 0.293 kg

<em><u>293.99 g potassium nitrate has to dissolve in water to absorb 101 kJ of heat. </u></em>     

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