To solve for the weighted average atomic weight of X, all
we have to do is to calculate for the contribution of each isotope. The
contribution of each isotope on the atomic weight of x is calculated by
multiplying their respective atomic weights with the abundance, therefore:
X – 28 = 27.977 amu * (92.23 / 100)
X – 28 = 25.803 amu
X – 29 = 28.976 amu * (4.67 / 100)
X – 29 = 1.353 amu
X – 30 = 29.974 amu * (3.10 / 100)
X – 30 = 0.929 amu
Hence:
X = X – 28 + X – 29 + X – 30
X = 25.803 amu + 1.353 amu + 0.929 amu
<span>X = 28.085 amu</span>
A) His wagon will accelerate more.
B) His wagon will accelerate less. Both parts are answered by F=ma. Mass is inversely proportional to acceleration, and force is directly proportional to acceleration.
Answer:
i believe the answer is B only because i looked it up on g00gle so take what i say with a GRAIN of salt all puns intended
Explanation:
Player A needs the least amount of energy. The ball is light weight and she is closest to the goal so the momentum need to kick the ball will be the least and the distance is has to travel is the shortest. But player C needs the most amount of energy. The ball is heavy so it will take the most momentum to move the ball and over such a long distance. Hope this help idrk.
Answer: 5.31 meters
Explanation: Use conservation of energy. Initial energy equals final energy. Initially, there is only kinetic energy (because height = 0 initially). At the end, kinetic energy equals 0 because at max height, there is max potential energy and the ball stops moving for a split second.
mgh = .5mv^2
Masses cancel out
gh = .5v^2
(9.8)(h) = .5(10.2^2)
Solve for h. h = 5.31 meters
