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2 years ago

6

If a 500-pound object is moved 200 feet how much work is being done?

1 answer:

Paha777 [63]2 years ago

4 0

Answer:

D

Explanation:

Work = Distance x Mass

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A hockey player makes a slap shot exerting a constant force of 40.0 newtons on the puck for .2 seconds. What is the magnitude of

Taya2010 [7]

Answer:

Magnitude of impulsive force is <u>8 N.s</u>.

Explanation:

Given:

Force acting on the puck is, $F=40.0\ N$

Time interval for which the force acts is, $\Delta t=0.2\ s$

We are asked to find the impulsive force.

Impulsive force acting on a body is the sudden change in the momentum of the body due to the application of a large constant force for a very small interval of time.

Here, the hockey player applies a large force of 40 N for a very short interval of time. So, the impact on the puck is measured as Impulse and is represented by 'J'.

Impulse in terms of applied force and time interval is given as:

$J=F\Delta t$

Plug in the given values and solve for 'J'. This gives,

$J=40\times 0.2\\J=8\ N\cdot s$

Therefore, the magnitude of impulsive force is 8 N.s.

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2 years ago

a log splitter puts out 1 100W of power for every 1500 W put into it. the efficiency of the machine is what

hram777 [196]

Answer:400 is the answer 1500-1100 is 400

Explanation:

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1 year ago

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How many electrons make up a charge of 3.5kC?

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21.8452851 * 10^21 e. Which is 21.845.285.100.000.000.000.000 electrons. A lot.

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2 years ago

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Be sure to answer all parts. Compare the wavelengths of an electron (mass = 9.11 × 10−31 kg) and a proton (mass = 1.67 × 10−27 k

Harrizon [31]

Explanation:

Given that,

(a) Speed, $v=6.66\times 10^6\ m/s$

Mass of the electron, $m_e=9.11\times 10^{-31}\ kg$

Mass of the proton, $m_p=1.67\times 10^{-27}\ kg$

The wavelength of the electron is given by :

$\lambda_e=\dfrac{h}{m_ev}$

$\lambda_e=\dfrac{6.63\times 10^{-34}}{9.11\times 10^{-31}\times 6.66\times 10^6}$

$\lambda_e=1.09\times 10^{-10}\ m$

The wavelength of the proton is given by :

$\lambda_p=\dfrac{h}{m_p v}$

$\lambda_p=\dfrac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 6.66\times 10^6}$

$\lambda_p=5.96\times 10^{-14}\ m$

(b) Kinetic energy, $K=1.71\times 10^{-15}\ J$

The relation between the kinetic energy and the wavelength is given by :

$\lambda_e=\dfrac{h}{\sqrt{2m_eK}}$

$\lambda_e=\dfrac{6.63\times 10^{-34}}{\sqrt{2\times 9.11\times 10^{-31}\times 1.71\times 10^{-15}}}$

$\lambda_e=1.18\times 10^{-11}\ m$

$\lambda_p=\dfrac{h}{\sqrt{2m_pK}}$

$\lambda_p=\dfrac{6.63\times 10^{-34}}{\sqrt{2\times 1.67\times 10^{-27}\times 1.71\times 10^{-15}}}$

$\lambda_p=2.77\times 10^{-13}\ m$

Hence, this is the required solution.

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2 years ago

Compare and contrast the average kinetic energy of 0.5 L of coffee at 34ÁC,

Andre45 [30]

Compared to coffee at room temperature, the molecules of the coffee at 34°C will be moving faster and colliding with one another more frequently.

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2 years ago