In this case, Coulomb's Law applies:
F = 1/(4πε₀) · (Q₁Q₂/r²)
You can solve it for r:
r = √[1/(4πε₀) · (Q₁Q₂/F<span>)]
Plugging in numbers:
r = </span>√[1/(4π·8.85×10⁻¹²) · (2.5×10⁻⁶)²/0.50]
= 0.335m
The correct answer is: the two charges are 0.335m apart.
The cost of running the lightbulb A for 30 days at 0.110 per KWh is 1.98
<h3>How to determine the energy </h3>
We'll beging by calculating the energy used by lightbulb A. This can be obtained as follow:
- Power (P) = 25 watts = 25 / 1000 = 0.025 KW
- Time (t) = 30 days = 30 × 24 = 720 h
- Energy (E) =?
E = Pt
E = 0.025 × 720
E = 18 KWh
<h3>How to determine the cost for running the bulb for 30 days</h3>
The cost of running the bulb for 30 days can be obtained as follow:
- Cost per KWh = 0.11
- Energy (E) = 18 KWh
- Cost =?
Cost = energy × Cost per KWh
Cost = 18 × 0.11
Cost = 1.98
Lean more about buying electrical energy:
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Answer:
a) 31.4 m/s
b) 50.2 m
Explanation:
a) When an object is free falling, its speed is determined by the gravity force giving it acceleration. Equation for the velocity of free fall started from the rest is:
v = g • t
g - is gravitational acceleration which is 9.81 m/s^2, sometimes rounded to 10
t - is the time of free fall
So:
v = 9.81 m/s^2 • 3.2
v = 31.4 m/s ( if g is rounded to 10, then the velocity is 10 • 3.2 = 32 m/s)
b) To determine the distance crossed in free fall we use the equation:
s = v0 + gt^2/2
v0 - is the starting velocity (since object started fall from rest, its v0 is 0)
s = gt^2/2
s = 9.81 m/s^2 • 3.2^2 / 2
s = 50.2 m (if we round g to 10 then the distance is 10 • 3.2^2/2 = 51.2 meters)