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horrorfan [7]
3 years ago
6

A sound wave is an example of an electromagnetic wave in nature?

Physics
1 answer:
AVprozaik [17]3 years ago
8 0
No. Sorry. A sound wave is a mechanical wave. There's nothing electromagnetic about it.
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A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the
Harman [31]

Answer:

The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.

<u>F1 = T- 46, 674.656 gm/s² </u>

Explanation:

<em>Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.</em>

To calculate the force caused by gravity on the basic pulley system we use the following equation:

F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g

∴ F2 = 4762.72g x 9.8 m/s²

= 46, 674.656 gm/s² or 46, 674.656 N

But since this F2 is acting in a downlowrd direction, it would be negative.

Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)

⇒ F1 = T - F2

<u>F1 = T- 46, 674.656 gm/s² </u>

4 0
3 years ago
A wave with a frequency of 80 Hz travels through rubber with a wavelength of 7.0 m. What is the velocity of the wave?
Scorpion4ik [409]

Answer:

560 m/s

Explanation:

Given,

Frequency ( f ) = 80 hz

Wavelength ( λ ) = 7.0 m = 7m

To find : Velocity ( v )

Formula : -

v = f λ

v = 80 x 7

v = 560 m/s

Hence, the velocity of the wave is 560 m/s.

5 0
2 years ago
Use ohms law to determine the battery voltage you would need to send 2.5 A of current through a light bulb with 3.6 Ω of resista
yan [13]

Answer:

285 or higher voltage

Explanation:

3 0
3 years ago
How does Newton describe the dependence of acceleration of a body on its mass and the net applied force?
tatiyna
<h2>Isaac Newton's First Law of Motion states, "A body at rest will remain at rest, and a body in motion will remain in motion unless it is acted upon by an external force." What, then, happens to a body when an external force is applied to it? That situation is described by Newton's Second Law of Motion.  </h2><h2> equation as ∑F = ma </h2><h2> </h2><h2>The large Σ (the Greek letter sigma) represents the vector sum of all the forces, or the net force, acting on a body.  </h2><h2> </h2><h2>It is rather difficult to imagine applying a constant force to a body for an indefinite length of time. In most cases, forces can only be applied for a limited time, producing what is called impulse. For a massive body moving in an inertial reference frame without any other forces such as friction acting on it, a certain impulse will cause a certain change in its velocity. The body might speed up, slow down or change direction, after which, the body will continue moving at a new constant velocity (unless, of course, the impulse causes the body to stop). </h2><h2> </h2><h2>There is one situation, however, in which we do encounter a constant force — the force due to gravitational acceleration, which causes massive bodies to exert a downward force on the Earth. In this case, the constant acceleration due to gravity is written as g, and Newton's Second Law becomes F = mg. Notice that in this case, F and g are not conventionally written as vectors, because they are always pointing in the same direction, down. </h2><h2> </h2><h2>The product of mass times gravitational acceleration, mg, is known as weight, which is just another kind of force. Without gravity, a massive body has no weight, and without a massive body, gravity cannot produce a force. In order to overcome gravity and lift a massive body, you must produce an upward force ma that is greater than the downward gravitational force mg.  </h2><h2> </h2><h2>Newton's second law in action </h2><h2>Rockets traveling through space encompass all three of Newton's laws of motion. </h2><h2> </h2><h2>If the rocket needs to slow down, speed up, or change direction, a force is used to give it a push, typically coming from the engine. The amount of the force and the location where it is providing the push can change either or both the speed (the magnitude part of acceleration) and direction. </h2><h2> </h2><h2>Now that we know how a massive body in an inertial reference frame behaves when it subjected to an outside force, such as how the engines creating the push maneuver the rocket, what happens to the body that is exerting that force? That situation is described by Newton’s Third Law of Motion.</h2><h2 />
4 0
3 years ago
An object of mass 0.50 kg is transported to the surface of Planet X where the object’s weight is measured to be 20 N. The radius
Olin [163]

Answer:

g'=40\ m.s^{-2}

Explanation:

Given:

  • mass of the object, m=0.5\ kg
  • weight of the object on planet x, W=20\ N
  • radius of the planet, R=4\times10^6\ m
  • radial distance between the planet and the object, r=2\times 10^6\ m

<u>Now free fall acceleration on planet X:</u>

W=m.g'

20=0.5\times g'

g'=40\ m.s^{-2} irrespective of the height.

8 0
3 years ago
Read 2 more answers
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