Answer:
Surface tension ____. a. is the inward force which tends to minimize the surface area of a liquid b. may be increased by detergents c. is decreased by hydrogen bonding d.
Note: option d is missing
The correct answer to the question is "option A (is the inward force which tends to minimize the surface area of a liquid)"
Explanation:
Surface tension is the most important for small fluid bodies. The surface comes under tension from the imbalanced forces and is often expressed as an amount of force exerted in the surface perpendicular to a line of unit length and it is a direct measure of energy loss per unit area of a surface.
The resistance that a surface shows against extension is a proof that an internal surface tension is present in the surface. Formula for measuring surface tension is: gamma equals force divided by length. The SI unit is newton per meter, dyne per centimeter is also used.
Water has a high surface tension because the water molecules on the surface are pulled together by strong hydrogen bonds. Surface tension of a liquid surface is that property of that liquid surface that makes it act like a stretched elastic sheet. Example of effect of surface tension on water is the flotation of objects denser than water, the separation of oil and water due to tension which arises in surface between dissimilar liquids. In the surface tension of liquid, the net force of attraction acting on the molecule is zero.
It’s literally in your reading go re reas
Answer:
a) A = 4.0 m
, b) w = 3.0 rad / s
, c) f = 0.477 Hz
, d) T = 20.94 s
Explanation:
The equation that describes the oscillatory motion is
x = A cos (wt + fi)
In the exercise we are told that the expression is
x = 4.0 cos (3.0 t + 0.10)
let's answer the different questions
a) the amplitude is
A = 4.0 m
b) the frequency or angular velocity
w = 3.0 rad / s
c) angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 3 / 2π
f = 0.477 Hz
d) the period
frequency and period are related
T = 1 / f
T = 1 / 0.477
T = 20.94 s
e) the phase constant
Ф = 0.10 rad
f) velocity is defined by
v = dx / dt
v = - A w sin (wt + Ф)
speed is maximum when sine is + -1
v = A w
v = 4 3
v = 12 m / s
g) the angular velocity is
w² = k / m
k = m w²
k = 1.2 3²
k = 10.8 N / m
h) the total energy of the oscillator is
Em = ½ k A²
Em = ½ 10.8 4²
Em = 43.2 J
i) the potential energy is
Ke = ½ k x²
for t = 0 x = 4 cos (0 + 0.1)
x = 3.98 m
j) kinetic energy
K = ½ m v²
for t = 00.1
²
v = A w sin 0.10
v = 4 3 sin 0.10
v = 1.98 m / s
Answer: 12 J
Explanation:
Work = force*displacement
Work= 3N*4m= 12 Joule