T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
Answer:
answer is the number 5
Step-by-step explanation:
First you square root 9 which is 3. Then u 3-1= 2. then u times 2 by 6 which equals = 12. Then minus 7 from this number. 12-7=5 ur number is 5.
The answer is 16.30.
Since the value is 16.25, 25 can be rounded to 30 since the value is over 5 cents.
ΔADB is a right triangle at ∠D
So, AB ⇒ Hypotenuse & AD,DB ⇒ Legs
∴
ΔADC is a right triangle at ∠D
So, AC ⇒ Hypotenuse & AD,DC ⇒ Legs
∴ BC= BD+ DC = 16 + 9 = 25
∴ The perimeter of triangle ABC = AB + BC + CA = 20 + 25 + 15 = 60.
<u>So, The correct answer is option C. 60</u>