Answer: 5.08 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
given mass of Cesium (Cs) = 675 g
Molar mass of Cesium (Cs) = 132.90 g/mol
Putting in the values we get:
![\text{Number of moles}=\frac{675g}{132.90g/mol}=5.08moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B675g%7D%7B132.90g%2Fmol%7D%3D5.08moles)
Thus there are 5.08 moles of cesium in 675 g of cesium.