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QveST [7]
4 years ago
15

How many moles of cesium (Cs) atoms are in 675g Cs?

Chemistry
2 answers:
sweet-ann [11.9K]4 years ago
8 0
The atomic mass of Cs is 132.9. So the mole number of 675 g cesium is 675/132.9 = 5.08 mole. Then the answer should be 5.08 mole.
timofeeve [1]4 years ago
3 0

Answer: 5.08 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

given mass of Cesium (Cs) = 675 g

Molar mass of Cesium (Cs) = 132.90 g/mol

Putting in the values we get:

\text{Number of moles}=\frac{675g}{132.90g/mol}=5.08moles

Thus there are 5.08 moles of cesium in 675 g of cesium.

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TIME REMAINING
otez555 [7]

Answer:

compound light microscope

6 0
3 years ago
La formula quimica de la molecula de agua H20 , si H = 1 gramos y O = 16 gramos . Cual es su composicion porcentual ? 88,88 % de
vesna_86 [32]

Answer:

88,88 % de O y 11,11 % de H

Explanation:

La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:

<em>Masa molar agua:</em>

2H = 2*1g/mol = 2g/mol

1O = 1*16g/mol = 16g/mol

Masa molar = 2 + 16 = 18g/mol

100g H2O * (1mol / 18g) = 5.556 moles H2O.

Moles de hidrógeno:

5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H

Moles Oxígeno = Moles H2O = 5.556 moles

La masa de hidrógeno es:

11.11mol * (1g/mol) 11.11g H

La masa de oxígeno es:

5.556 mol * (16g / 1mol) = 88.89g O

Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:

<h3>88,88 % de O y 11,11 % de H</h3>
7 0
3 years ago
Please help me with this chemistry question
aliina [53]

Answer:

A.

Explanation:

8 0
3 years ago
a quantity of gas has a volume of 400.0 mL when confined under a pressure of 600.0mm Hg. what will be the new volume of the gas
Alex787 [66]

Answer:

1200 mL

Explanation:

Given data

  • Initial pressure (P₁): 600.0 mmHg
  • Initial volume (V₁): 400.0 mL
  • Final pressure (P₂): 200.0 mmHg
  • Final volume (V₂): ?

For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL

3 0
3 years ago
Multiply or divide to find the equivalent fraction.<br><br> 51/120=□/360
jok3333 [9.3K]

Answer

153

Explanation:

51/120 = x/360

51(360) = 120x

18360 = 120x

18360/120x = 120x/120x

153 = x

5 0
3 years ago
Read 2 more answers
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