Crush the limestone... it would give more area for the acid to react
Answer:
6 mol/min
Explanation:
2A+2B→4C
The relationship between the reactants and products of this equation is given by;
1/2 -d[A]/dt = 1/2 -d[B]/dt = 1/4 d[C]/dt
Our focus is on A and C
From the question;
d[A]/dt = 3mol/min
We have;
1/2 (3) = 1/4 d[C]/dt
d[C]/dt = 4/2 * 3 = 6 mol/min
Answer:
Explanation:
The difference between Polycrystalline and Amorphous materials is given as:
Polycrystalline:
- The atoms in the crystal lattice are arranged in an ordered manner.
- The particles in the crystal posses a particular geometry
- The crystal lattice have a specific temperature known as its Melting Point.
Amorphous:
- There is no specific order in the arrangement of particles in the crystal.
- They do not have any particular geometry.
- There is no specific temperature but a range of temperature in which the crystal melts.
The properties of crystalline materials can be constrained by modifying the grain size at the hour of the amalgamation. The mechanical properties can be improved by choosing the grain size so that the quantity of disengagements and grain limits are expanded.
Usually this should be possible by diminishing the grain size, yet it additionally relies on a ton of different elements relying on the application. The quality of the material is expanded when the grain size is decreased.
Usefulness of smaller grains:
At the point when the size of the grains is decreased to a degree of 100 nm to 1000 nm, we can say we had acquired smaller grain which can be called as ultra-fine grain materials.
These can be utilized widely for the assembling of nanomaterial which are having a tremendous assortment of utilization and the new regions of use are expanding by step by step.
Usefulness of smaller grains:
Larger grains size is valuable in light dissipating applications, huge size grain has high perceivability to the light and it very well may be utilized in dispersing applications. Larger molecule size is utilized in specific responses to restrict the reactivity to a specific degree.
Applications of Amorphous Material:
- The amorphous carbon is utilized for the production of Ta-C films which can be utilized for the applications in ultra-flimsy defensive coatings for attractive plates, in cells, batteries and sun powered cells, to keep up inactive layers in electronic gadgets, etc.
- Amorphous silicon is utilized for the assembling of the Thin Film Transistor (TFT) which is in the end be utilized for computerized x-beam picture detecting, coordinated shading sensors, sensors for CMOS cameras, light-radiating diodes, and so on.
Answer:
pH = 11, The solution is Basic.
Explanation:
We know that;
[OH-] [H+] = 1 × 10^-14
we are given; [OH-] as 1 x 10^ -3 M
Therefore, we can get the [H+] by;
[H+] = 1 × 10^-14/[OH-]
= 1 × 10^-14 M/1 x 10^ -3 M
= 1 × 10^-11 M
But; pH = - log [H+]
Thus,
pH = - log (1 ×10^-11 M)
= 11
pH = 11, which means the solution is basic.
