A student takes a stock solution that is 50 mM (solute formula weight is 120.5 g/mol) and prepares a series of solutions. The fi
1 answer:
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Answer:
Explanation:
Hello,
In this case, since the chemical reaction is:
We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:
In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:
Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:
Then, since the concentration and the volume define the moles, we can write:
Therefore, the neutralized volume turns out:
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Answer:
B
Explanation:
This question is about stoichiometry. From the balanced equation ⇒
, we see that 3 moles of water is needed to react with 1 mole of
.
This means that, to fully react 3.62 moles of , we would need 3*3.62 or 10.86 moles of water. However, we only have 6.31 moles, so water is the limiting reactant.
Since 3 moles of water react with 1 mole of , 6.31 moles of water can fully react with 6.31÷3 or 2.1033 moles of
.
From the balanced equation, we see that every mole of reacted gets you 2 moles of
. Therefore, 2.1033 moles of
would give you approximately 4.21 moles of
.