D = M/V = 76g / 22ml = 3.4g/ml
Half ~ D = 38g / 11ml = 3.4g/ml
Even if the object you had was cut in half, it’s density would remain the same.
Li2CO3 + 2HNO3 ----> 2LiNO3 + H2O + CO2
The amount of W(OH)2 needed would be 448.126 g
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
W(OH)2 + 2 HCl → WCl2 + 2 H2O
The mole ratio of W(OH)2 to HCl is 1:2
Mole of 150g HCl = 150/36.461
= 4.11 moles
Equivalent mole of W(OH)2 = 4.11/2
= 2.06 moles
Mass of 2.06 moles W(OH)2 = 2.06 x 217.855
= 448.188g
More on stoichiometric calculations can be found here: brainly.com/question/8062886
From increasing atomic mass. He also made groups and periods.
I'm not sure, but maybe burning point...
