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cestrela7 [59]
3 years ago
13

The degree to which various compounds will dissociate in solution varies greatly.

Chemistry
1 answer:
uranmaximum [27]3 years ago
5 0

Answer: True

Explanation:

Weak electrolytes are those solutions which do not undergo complete dissociation when dissolved in water. The dissociation of weak electrolytes is given by an equilibrium.

Example: CH_3COOH\rightleftharpoons CH_3COO^-+H^+

Strong electrolytes are those solutions which undergo complete dissociation when dissolved in water.  The dissociation of strong electrolytes is given by a right arrow.

Example: HCl\rightarrow H^++Cl^-

Thus the degree to which various compounds will dissociate in solution varies greatly is true.

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Vikki [24]

2nd

Explanation:

because i guesses i guess so yeah trust your gut buddy

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3 years ago
Precipitation _____. occurs equally all over the globe. is the change in state from a gas to a liquid. happens when ice changes
babunello [35]

Precipitation exceeds evaporation over the land.

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3 years ago
Calculate the final Celsius temperature when 634 L at 21 °C is compressed to 307 L.
Illusion [34]

Answer:

- 130.64°C.

Explanation:

  • We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.

V₂ = 307.0 L, T₂ = ??? K.

<em>∴ T₂ = V₂T₁/V₁ </em>= (307.0 L)(294.0 K)/(634.0 L) = <em>142.36 K.</em>

<em>∴ T₂(°C) = 142.36 K - 273 = - 130.64°C.</em>

5 0
3 years ago
Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter
Dominik [7]
I hope this helps you.

5 0
3 years ago
What mass of propane could burn in 48.0 g of oxygen? C3H8 + 5O2 → 3CO2 + 4H2O
Ipatiy [6.2K]

Answer:

Mass = 13.23 g  

Explanation:

Given data:

Mass of oxygen = 48.0 g

Mass of propane burn = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂     →      3CO₂ + 4H₂O

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 48.0 g/ 32 g/mol

Number of moles = 1.5 mol

now we will compare the moles of propane and oxygen.

              O₂           :          C₃H₈

               5            :            1

             1.5            :          1/5×1.5 = 0.3 mol

Mass of propane burn:

Mass = number of moles × molar mass

Mass = 0.3 mol × 44.1 g/mol

Mass = 13.23 g  

6 0
3 years ago
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