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cestrela7 [59]
3 years ago
13

The degree to which various compounds will dissociate in solution varies greatly.

Chemistry
1 answer:
uranmaximum [27]3 years ago
5 0

Answer: True

Explanation:

Weak electrolytes are those solutions which do not undergo complete dissociation when dissolved in water. The dissociation of weak electrolytes is given by an equilibrium.

Example: CH_3COOH\rightleftharpoons CH_3COO^-+H^+

Strong electrolytes are those solutions which undergo complete dissociation when dissolved in water.  The dissociation of strong electrolytes is given by a right arrow.

Example: HCl\rightarrow H^++Cl^-

Thus the degree to which various compounds will dissociate in solution varies greatly is true.

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4. Given the balanced equation: 2Na + S → Na₂S
PtichkaEL [24]

Answer:

Option D. 30 g

Explanation:

The balanced equation for the reaction is given below:

2Na + S —> Na₂S

Next, we shall determine the masses of Na and S that reacted from the balanced equation. This is can be obtained as:

Molar mass of Na = 23 g/mol

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Mass of S from the balanced equation = 1 × 32 = 32 g

SUMMARY:

From the balanced equation above,

46 g of Na reacted with 32 g of S.

Finally, we shall determine the mass sulphur, S needed to react with 43 g of sodium, Na. This can be obtained as follow:

From the balanced equation above,

46 g of Na reacted with 32 g of S.

Therefore, 43 g of Na will react with = (43 × 32)/46 = 30 g of S.

Thus, 30 g of S is needed for the reaction.

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2 years ago
How many milliliters of a 0.266 m lino3 solution are required to make 150.0 ml of 0.075 m lino3 solution?
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We need an equation that would relate the concentration of the original solution to that of the desired solution. To solve this we use the equation expressed as follows, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

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Therefore, we need about 42.29 mL of the 0.266 M of lithium nitrate solution to make 150.0 mL of the 0.075 M lithium nitrate solution.

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3 years ago
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