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3 years ago

The degree to which various compounds will dissociate in solution varies greatly.

Chemistry

1 answer:

uranmaximum [27]3 years ago

5 0

Answer: True

Explanation:

Weak electrolytes are those solutions which do not undergo complete dissociation when dissolved in water. The dissociation of weak electrolytes is given by an equilibrium.

Example: $CH_3COOH\rightleftharpoons CH_3COO^-+H^+$

Strong electrolytes are those solutions which undergo complete dissociation when dissolved in water. The dissociation of strong electrolytes is given by a right arrow.

Example: $HCl\rightarrow H^++Cl^-$

Thus the degree to which various compounds will dissociate in solution varies greatly is true.

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The first law of thermodynamics is observed when

krek1111 [17]

Answer:

Explanation:

The first law of Thermodynamics is known as Conservation because it explains that energy is always maintained within a closed system and cannot be created or destroyed. Therefore, this is observed when there is no longer change in temperature in a system. Mainly because the energy is not being transferred to and from another system. Without this transfer of energy, the energy itself gets conserved within the system and the temperature no longer fluctuates.

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2 years ago

PLEASE PLEASE PLEASE ANSWER HAVE MERCY 35 POINTS

Arada [10]

You should give answers since some people will just try and find any answer, which happened to me. So like if you have answers for the question just put them like A B C D kinda like true or false for others to know what they got instead of giving them more work, and then they just give you random answers.

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3 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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3 years ago

When the equation Eg(s) + DnGO4(aq) ---> Dn(s) + Eg2(GO4)3(aq) is balanced, what is the coefficient in

Artemon [7]

B) 2

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3 years ago

Which of the following ion is the least and the most hydrated? OH- , Li+, K+, Na+

vodomira [7]

I don’t know either lol

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2 years ago