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Hatshy [7]
3 years ago
8

How many atoms of carbon (C,12.01 g/mol) are in a diamond with a mass of 0.568 g?

Chemistry
1 answer:
Fantom [35]3 years ago
5 0

2.85 × 10^22. A diamond with a mass of 0.568 g contains

2.85 × 10^22 atoms C.

Diamond is a form of pure carbon.

a) Convert <em>grams of C to moles of C</em>

Moles of C = 0.568 g C × (1 mol C/12.01 g C) = 0.047 29 mol C

b) Convert <em>moles of C to atoms of C </em>

Atoms of C = 0.047 29 mol C × (6.022 × 10^23 atoms C)/(1 mol C)

= 2.85 × 10^22 atoms C

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Answer:

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A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

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You might see the equation both ways.

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C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

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Take a look at the attachment below

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<em>Hope that helps!</em>

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