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Aleksandr-060686 [28]
3 years ago
8

Help please ❤️ When O2 is added to the melted candy mixture once it has cooled. Why would it not be beneficial to add the CO2 af

ter it is first melted?
Chemistry
1 answer:
amm18123 years ago
8 0

it wouldnt have an effect?

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How many fluorine atoms bond with calcium to form calcium fluoride? one two three four five
Elena-2011 [213]
Calcium fluoride.
Ca is metal, F is non-metal, so they form ionic bond.
Ca as metal can form only positive ion. Ca in the second group, so the charge of Ca ion is 2+.   Ca²⁺
F is in the 17th group, so it has 7 electrons on the last level. It is non-metal, non-metal, so it has negative charge -(8-7)=-1. "8" because on the last level cannot be more than 8 electrons. F-ion is F¹⁻.

Ca²⁺  F¹⁻
Number of positive charges should be equal to number of negative charges,
Formula of calcium fluoride
CaF2.
2 atoms Fluorine bond with Calcium.
7 0
3 years ago
pplication)Using multiple models simultaneously: This FNT refers to a processinvolving three moles of a diatomic gas (which beha
Fiesta28 [93]

Complete Question

Questions Diagram is attached below

Answer:

*  W=1142.86Joule

*  Q=997.7J

*  H=2140.5J

Explanation:

From the question we are told that:

Temperature T=337K

Pressure P=(60-55)Pa*10^5

VolumeV=(1.6-1.4)m^3*10^{-3}

Generally the equation for gas Constant is mathematically given by

\frac{P_2}{P_1}=\frac{V_1}{V_2}^n

 \frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n

 n=0.65

Therefore

Work-done

 W=\int{pdv}

 W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}

 W=1142.86Joule

Generally the equation for internal energy is mathematically given by

 Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}

 Q=997.7J

Therefore

 H=Q+W

 H=997.7J-11.42.9

 H=2140.5J

5 0
2 years ago
Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0
3 years ago
The diameter of metal wire is often referred to by its American wire-gauge number. A 16 gauge-wire has a diameter of 0.05082 in.
lubasha [3.4K]

Answer:

length of wire = 38.82 m

Explanation:

∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm

∴ m spool = 1 Lb = 453.592 g

∴ ρ = 8.92 g/cm³

cross section area:

⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²

⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )

⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m

8 0
3 years ago
An object has a mass of 20 kg and a volume of 5 mL. What is the object's density?
e-lub [12.9K]
Good grief, this stuff got caught in a black hole somewhere. It is terribly dense.
1 mL = 1 cc under normal conditions.

d = mass / volume
m = 20 kg
v = 5 mL

d = 20kg / 5 mL
d = 4 kg / mL
d = 4 kg / cc

A <<<<answer
7 0
3 years ago
Read 2 more answers
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