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xxMikexx [17]
3 years ago
14

Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The lengt

h of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.
Physics
2 answers:
Zanzabum3 years ago
8 0
<span>Days and nights are equal in length everywhere.(gradpoint)</span>
Nana76 [90]3 years ago
5 0

Answer: Days and nights are equal in length everywhere.

Explanation:

Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.

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If the capacity of the lungs of an adult were 3.8 L, how many moles of air would the lungs contain at body temperature and atmos
Ahat [919]

Answer:

  • 0.14955  mol

Explanation:

We can solve this problem using the ideal gas law

P \ V = \ n \ R \ T

where P is the pressure, V the volume, n the number of moles, R the ideal gas constant and T the temperature.

We can use the atmospheric pressure as 1 atm, and the body temperature as 36.5 °C, in Kelvin this is:

T_{body} = 36.5 \° C = (36.5 + 273.15) K = 309.65 \ K

The ideal gas constant is:

R = 0.082057 \frac{L \ atm}{ K \ mol}

taking all this in consideration, the number of moles will be:

n = \frac{P \ V}{  R \ T }

n = \frac{1 \ atm * 3.8 \ L  }{ 0.082057 \frac{L \ atm}{ K \ mol} *  309.65 \ K } [/tex]

n = 0.14955 \ mol

3 0
3 years ago
Elmotordeuncarroda2000revolucionesporminuto<br><br> .Calcularsuperíodoysufrecuencia.
Andrew [12]

can u translate pls

Explanation:

5 0
3 years ago
A 70 kg object strikes the ground with 2500 J of KE after falling freely from rest. How far above the ground was the object when
Kitty [74]

Answer:

3.64 m

Explanation:

m = Mass of object = 70 kg

Kinetic energy of the object = 2500 J

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

h = Height from which the object is dropped

Kinetic energy is given by

\dfrac{1}{2}mv^2=2500\\\Rightarrow v^2=\dfrac{2\times 2500}{70}

From conservation of energy we get kinetic energy equal to potential energy.

\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{1}{2g}v^2\\\Rightarrow h=\dfrac{1}{2\times 9.81}\times \dfrac{2\times 2500}{70}\\\Rightarrow h=3.64\ \text{m}

The object was released from a height of 3.64 m.

6 0
3 years ago
The diagram below shows how sunlight is radiated back into the Earth's atmosphere as heat (infrared radiation).
Juliette [100K]

The diagram that shows how sunlight is radiated back into the Earth’s atmosphere as heat(infrared radiation) is of the Greenhouse effect.

The greenhouse effect is a natural phenomenon that occurs on Earth and heats up our atmosphere.

The name of this effect is derived from a greenhouse, which is used to grow crops in a special environment.

A greenhouse is basically a house that is made up of glass. The glass allows heat to enter the house but it does not allow the heat to escape to the outside thus keeping the greenhouse warm.

Some gases that are responsible for this effect are known as greenhouse gases. These gases are carbon dioxide, methane, chloro- fluoro carbons, etc.

These gases trap the heat of the sun and raise the temperature of Earth thus causing global warming.

Thus, the diagram that shows how sunlight is radiated back into the Earth’s atmosphere as heat(infrared radiation) is of the Greenhouse effect.

Read more about Greenhouse effect:

brainly.com/question/13390232

#SPJ1

6 0
1 year ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
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