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xxMikexx [17]
3 years ago
14

Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The lengt

h of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.
Physics
2 answers:
Zanzabum3 years ago
8 0
<span>Days and nights are equal in length everywhere.(gradpoint)</span>
Nana76 [90]3 years ago
5 0

Answer: Days and nights are equal in length everywhere.

Explanation:

Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.

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If average acceleration is calculated using the equation, “change in velocity / change in time,” what is an objects acceleration
harina [27]

Answer:

Acceleration of object=8cm/s^{2}

Explanation:

Given:-

Velocity (v)=24 cm/s

Time (t)=3 s

To calculate acceleration (a) of object=?

Now,

acceleration =\frac{velocity}{time}

a=\frac{v}{t}

a=\frac{24}{3}

a=8 cm/s^{2}

Therefore object acceleration =8cm/s^{2}

7 0
3 years ago
If you enjoy teaching small or large glasses and being active every day which career would be a good fit for you
tino4ka555 [31]

Your preferences would fit well with the careers of bar-tending, optometry, or school teaching.

6 0
3 years ago
(a) If the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you ca
Colt1911 [192]

a) 52.5 m

b) 16.0 m/s

Explanation:

a)

The motion of a car slowed down by friction is a uniformly accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where

v = 0 is the final velocity (the car comes to a stop)

u = 28.7 m/s is the initial velocity of the car

a is the acceleration

s is the stopping distance

For a car acted upon the force of friction, the acceleration is given by the ratio between the force of friction and the mass of the car, so:

a=\frac{-\mu mg}{m}=-\mu g

where:

\mu=0.80 is the coefficient of friction

g=9.8 m/s^2 is the acceleration due to gravity

Substituting and solving for s, we find:

s=\frac{v^2-u^2}{-2\mu g}=\frac{0-(28.7)^2}{-2(0.80)(9.8)}=52.5 m

b)

In this case, the car is moving on a wet road. Therefore, the coefficient of kinetic friction is

\mu=0.25

Here we want the stopping distance of the car to remain the same as part a), so

s=52.5 m

We can use again the same suvat equation:

v^2-u^2=2as

And since the final velocity is zero

u = 0

We can find the initial velocity of the car:

v=\sqrt{2as}=\sqrt{2\mu gs}=\sqrt{2(0.25)(9.8)(52.5)}=16.0 m/s

7 0
3 years ago
A gold bar 20.0kg at 35.0°c is placed in a large insulated 0.8kg glass container at 15°c and 2.0kg of water at 25°c.. calculate
Oksanka [162]

Answer:

The final equilibrium temperature is approximately 26.69 °C

Explanation:

The heat transferred, ΔQ, from a hot body to a cold one is given by the following formula;

ΔQ = m·c·ΔT

Where;

m = The mass of the body

c = The specific heat capacity of the body

ΔT = The temperature change of the body

The given mass of the gold bar, m₁ = 20.0 kg

The initial temperature of the gold bar, T₁ = 35.0 °C

The specific heat capacity of gold, c₁ = 0.13 kJ/(kg·K)

The mass of the glass container, m₂ = 0.8 kg

The initial temperature of the glass container, T₂ = 15°C

The specific heat capacity of glass, c₂ = 0.792 kJ/(kg·K)

The mass of the added water, m₃ = 2.0 kg

The initial temperature of the added water, T₃ = 25°C

The specific heat capacity of water, c₃ = 4.2 kJ/(kg·K)

The heat lost by the gold = The heat gained by the glass and the water

Let 'T' represent the temperature at the final equilibrium, we have;

m₁·c₁·ΔT₁ = m₂·c₂·ΔT₂ + m₃·c₃·ΔT₃

Where;

ΔT₁ = T₁ - T

ΔT₂ = T - T₂

ΔT₃ = T - T₃

∴ 20.0 × 0.13 × (35 - T) = 0.8 × 0.792 × (T - 15) + 2.0 × 4.2 × (T - 25)

Expanding and collecting like terms (using a graphing calculator) gives;

91 - 2.6·T = 9.0336·T - 219.504

9.0336·T + 2.6·T = 219.504 + 91 = 310.504

11.6336·T = 310.504

T = 310.504/11.6336 ≈ 26.69

The final equilibrium temperature, T ≈ 26.69 °C.

4 0
3 years ago
Qualitative studies draw conclusions.<br> True<br> False
Marina86 [1]

Answer:

Hey there!

This is false. A qualitative study is about how a thing looks, not based on any mathematical or scientific data. Quantitative studies, on the other hand, draw conclusions.

Let me know if this helps :)

3 0
3 years ago
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