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xxMikexx [17]
3 years ago
14

Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The lengt

h of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.
Physics
2 answers:
Zanzabum3 years ago
8 0
<span>Days and nights are equal in length everywhere.(gradpoint)</span>
Nana76 [90]3 years ago
5 0

Answer: Days and nights are equal in length everywhere.

Explanation:

Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.

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49. \ A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner
faust18 [17]

Answer:

    \frac{L_1}{L_2} = \sqrt{(n^2 - 1)}

Explanation:

For this interesting problem, we use the definition of centripetal acceleration  

      a = v² / r  

angular and linear velocity are related  

     v = w r  

we substitute  

    a = w² r

the rectangular body rotates at an angular velocity w  

We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A  

the distance OB = L₂  

the distance AB = L₁

the sides of the rectangle  

It is indicated that the acceleration in in A and B are related  

      a_A = n \ a_B  

we substitute the value of the acceleration  

    w² r_A = n r_B  

the distance from the each corner is  

    r_B = L₂  

    r_A = \sqrt{L_1^2 + L_2^2}  

we substitute  

   \sqrt{L_1^2 + L_2^2} = n L₂  

    L₁² + L₂² = n² L₂²  

    L₁² = (n²-1) L₂²  

4 0
3 years ago
Two long, straight wires, one above the other, are seperated by a distance 2a2a and are parallel to the x−axisx−axis. Let the +y
kompoz [17]

Answer:

note:

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</u>

Download docx
3 0
3 years ago
Neon atoms at 245 K pass through a fan that gives each mole of neon gas an additional kinetic energy of 16.0 J. Part A What is t
hjlf

Answer:

246.28 K

Explanation:

The total energy of one mole of gas molecules can be calculated by the formula given below

E = \frac{3}{2}\times R\times T

Where R is gas constant and T is absolute temperature.

Put the value of R as 8.314 and temperature as 245 , we get

E = \frac{3}{2}\times 8.314\times 245

= 3055.4 J

Add 16 j to it

Total energy of gas molecules = 3055.4 + 16 = 3071.4 J.

If T be the temperature after addition of energy then

\frac{3}{2}\times 8.314\times T = 3071.4

T =\frac{2\times 3071.4}{3\times 8.314}

T = 246.28 K

7 0
3 years ago
Which statements about acceleration are true?
bonufazy [111]
It's definitely not B or C. There are things missing from A and D so we can't narrow it down any farther.
4 0
3 years ago
NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supp
IRINA_888 [86]

Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supply storage area of the lunar outpost where gravity is 1.63m/s/s can only support 1 x 10 over 5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost?

Answer:

601000 N

Explanation:

Given that :

Acceleration due to gravity at lunar outpost = 1.6m/s²

Supported Weight of supplies = 1 * 10^5 N

Acceleration due to gravity on the earth surface = 9.8m/s²

Maximum weight of supplies as measured on EARTH :

Ratio of earth gravity to lunar post gravity:

(Earth gravity / Lunar post gravity) ;

(9.8 / 1.63) = 6.01

Hence, maximum weight of supplies as measured on EARTH should be :

6.01 * (1 × 10^5)

6.01 × 10^5

= 601000 N

3 0
3 years ago
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