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xxMikexx [17]
3 years ago
14

Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The lengt

h of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.
Physics
2 answers:
Zanzabum3 years ago
8 0
<span>Days and nights are equal in length everywhere.(gradpoint)</span>
Nana76 [90]3 years ago
5 0

Answer: Days and nights are equal in length everywhere.

Explanation:

Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.

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Homework: Making Connections to Science Ideas
natita [175]

The patterns that can be looked for when studying science topic include the use of data or carrying out an experiment.

<h3>How to illustrate the information?</h3>

It should be noted that patterns are regular and intelligible forms or sequences that can be found in nature. Based on the information, scientific questions may be generated when scientists want to observe a pattern of events.

It should be noted that when scientists want to observe a pattern of events or

when something does not match an established pattern, scientists can use patterns to classify objects or phenomena into groups.

Therefore, the patterns that can be looked for when studying science topic include the use of data or carrying out an experiment.

Learn more about patterns on:

brainly.com/question/968894

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4 0
2 years ago
Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.380 m. The engine of th
Vilka [71]

Answer:

The magnitude of the static frictional force is 1200 N

Explanation:

given information :

radius, r = 0.380 m

applied-torque, τ1 = 456 N

The car has a constant velocity, thus the acceleration is zero

α = 0

Στ = I α

τ1 - τ2 = I α

τ2 = counter-torque

τ1 - τ2 = 0

τ1 = τ2

r x F_{s} = τ1

F_{s} = the static frictional force (N)

F_{s} = τ1 /r

  = 456 N/0.380 m

  = 1200 N

7 0
3 years ago
Can two objects exert a force on each other without touching? example
lara [203]

Answer:

where is the example...?

7 0
3 years ago
A flat metal washer is heated. As the washer's temperature increases, what happens to the hole in the center? A flat metal washe
STALIN [3.7K]

To solve this exercise it is necessary to take into account the concepts related to thermal expansion.

The thermal expansion is given by the function,

\Delta L = L_0 \alpha \Delta T

Where,

\Delta L= Change in Length

\Delta T =Change in Temperature

\alpha =Coeficiente de dilatación lineal

L_0 = Initial Length

By quickly deducing the formula, we can realize that the greater the change in temperature, the greater the change in the length of the radius.

The change in length is proportional to the change in temperature. Considering that the other two terms are constant we have that the correct one would be: <em>The hole in the center of the washer will expand.</em>

4 0
3 years ago
A client with hypertension who weighs 72.4 kg is receiving an infusion of nitroprusside (Nipride) 50 mg in D5W 250 ml at 75 ml/h
Mkey [24]

To solve this problem it is necessary to simply apply the concepts related to cross-multiply and proportion between units.

Let's start first by relating the amount of dose needed to be supplied per hour, in other words,

The infusion of 250ml should be supplied at a rate of 75ml / hour, so what amount x of mg hour should be supplied with 50Mg.

\frac{x}{75ml/hour} \rightarrow \frac{50mg}{250ml}

x \rightarrow \frac{50mg*75ml/hour}{250ml}

x \rightarrow \frac{3750mg}{250hour}

x \rightarrow 15\frac{mg}{hour}

Converting to mcg units we know that 1mg is equal to 1000mcg and that 1 hour contains 60 min, therefore

x \rightarrow 15\frac{mg}{hour}

x \rightarrow 15\frac{mg}{hour}(\frac{1000mcg}{1mg})(\frac{1hour}{60min})

x \rightarrow 250mcg/min

The dose should be distributed per kilogram of the patient so if the patient weighs 72.4kg,

Dose = \frac{250mcg/min}{72.4kg}

Dose = 3.5 \frac{mcg/min}{kg}

Therefore the client will receive 3.5mcg/kg/min.

8 0
3 years ago
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