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natka813 [3]
3 years ago
13

What do you understand by upthrust Force​

Physics
1 answer:
Sedaia [141]3 years ago
7 0

Answer:

hope you like it

Explanation:

An object that is partly, or completely, submerged experiences a greater pressure on its bottom surface than on its top surface. This causes a resultant force upwards. This force is called upthrust . The upthrust force is equal in size to the weight of the fluid displaced by the object.

Buoyancy or upthrust, is an upward force exerted by a fluid that opposes the weight of an immersed object.It is the force that pushes an object up. The upthrust, or buoyancy, keeps ships afloat. The upthrust, or buoyancy, keeps swimmers on top of the water.

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A joule is equivalent to<br><br> N/s<br> N/m<br> Ndm<br> Nds
skelet666 [1.2K]
A joule is also called a newton metre so it is force in newtons multiplied by distance. Answer 3 seems to fit, assuming dm means “delta m” or a measure of the change of distance in metres.
7 0
4 years ago
Name a device that converts mechanical energy into electrical energy.
erma4kov [3.2K]

Answer:

Electric generator is the device that converts mechanical energy into electrical energy

4 0
3 years ago
Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to
andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3   ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3  ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = \frac{m1v}{3v3}  -----  ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 =  2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1  hence v2 = 2v1  where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴  v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

8 0
3 years ago
Truck A has a mass of 5000 kg and a velocity of +5m/s. Explain why we say truck B has a velocity of -5m/s.
frez [133]
Velocity is a vector, which includes both magnitude and direction. Negative velocity means that B is travelling in an opposite direction of A.
4 0
3 years ago
A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t
Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

KE = PE

\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

q_{1,2} = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}

Replacing,

q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}

q_2 = 3.6531nC

Therefore the charge on the sphere is 3.6531nC

4 0
3 years ago
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