Answer:
a. when the acceleration of the objects become negative
The effective temperature of a star is relative to the
fourth root of the luminosity and is contrariwise proportional to the square
root of the radius.
L = k R² T⁴
If the radius remains continuous, while the luminosity doubles, the temperature
must increase by a factor of the fourth root of two.
If L → 2L, then T → 1.189207115 T
So the answer is approximately 1.19 times.
E = 0.5mv^2 = 0.5*44*10^2 = 2200J
Density is varying through the world’s oceans. The density of ocean water is not uniform.
Explanation:
PE= mgh
6 J= (3m) (9.81 m/s2) (mass)
mass=( 6)/(3×9.81)
mass= 0.20 Kg
