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TiliK225 [7]
3 years ago
7

(ANSWER FAST) Three resistors of 1 Ω, 2 Ω and 3 Ω are connected in parallel. what should be The combined resistance of the three

resistors?
options:
a)Less than 1 Ω
b)Equals 2Ω
c)Between 2Ω and 3Ω
d)Greater than 3 Ω
Physics
2 answers:
____ [38]3 years ago
8 0

Answer:

less than 1 ohm

Explanation:

Dafna1 [17]3 years ago
7 0

The combined resistance is 0.545 ohm. That's less than 1 ohm.

The combined resistance of several resistors in parallel is always less than the smallest individual one.

(Several roads in parallel can always carry more traffic than the single widest, fastest, smoothest road.)

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A. If a T-Rex runs 20 meters in 4 seconds, what is it’s average speed?
mariarad [96]

5m/s

100m

Explanation:

Average speed is sum of distance distance traveled in a given time by a body.

 Average speed= \frac{total distance covered}{time taken}

Distance = 20m

time = 4s

  Average speed = \frac{20}{4} = 5m/s

For the spaceship;

   Distance covered = speed x time

Speed = 50m/s

time = 2s

 Distance covered = 50 x 2 = 100m

learn more:

Average speed brainly.com/question/5063905

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3 0
3 years ago
An atom of sodium (Na) gives up an electron to chlorine (Cl) to form table salt. What type of bond is this?
Alexxx [7]
Your answer will be C!~
6 0
3 years ago
A mosquito can fly with a speed of 1.10 m/s with respect to the air. Suppose a mosquito flies east at this speed across a swamp.
sineoko [7]

Answer:

The velocity of Mosquito with respect to earth will be 0.302m/s

Explanation:

V(ma) = 1.10 m/s, east  Velocity of mosquito with respect to air

V(ae) = 1.4 m/s at 35°  Velocity of air with respect to Earth in west of south direction.

Velocity of Mosquito with respect to earth will be  

V(me) = V(ma) + V(ae)

We need to find the mosquito’s speed with respect to Earth in the x direction.

V(x, me) = V(x, ma) + V(x, ae) = V(ma) + V(ae)(cos theta(ae) )

Angle (ae) = –90.0° − 35°=−125°

V(x, me) = 1.10 + (1.4)Cos(-125)

             = 1.10 + 1.4(-0.57)

             = 1.10 -0.798

              = 0.302

So the velocity of Mosquito with respect to earth will be 0.302m/s

7 0
3 years ago
A 22-g bullet traveling 265 m/s penetrates a 1.9 kg block of wood and emerges going 125 m/s .
Usimov [2.4K]

The body moves at a velocity of 1.62m/s after the bullet emerges.

<h3>Given:</h3>

Mass of bullet, m_1 = 22g

                               = 0.022 kg

Mass of the block, m_2 = 1.9 kg

Velocity of bullet , v_1 = 265 m/s

v_2 = 0

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.

After penetration;

v^{'}_1 =125 m/s

v^{'}_2=?

The formula for calculating the collision of a body is expressed as:

p = mv

m is the mass of the body

v is the velocity of the body

∴ Momentum before = Momentum after

Substitute the given parameters into the formula as shown:

   m_1v_1+ m_2v_2 = m_1v^{'}_1+ m_2v^{'}_2\\0.022* 265 + 0 = 0.022*125+1.9*v^{'}_2\\5.83 = 1.9 v^{'}_2\\v^{'}_2 = 1.62 m/s

Therefore, It moves with a velocity of 1.62 m/s.

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brainly.com/question/25121535

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6 0
1 year ago
Pitbulllover101
mafiozo [28]

Some of the heavy particles bounced off the foil, because there are positive particles spread throughout the atom

7 0
3 years ago
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