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Ratling [72]
3 years ago
12

How does the force due to gravity on Mars compare to the force due to gravity on Earth? , and Using Newton's Second Law, explain

how a rocket can have an increase in acceleration over time.
Physics
1 answer:
zubka84 [21]3 years ago
4 0
As accurately described by Einstein's theory of relativity, gravity is not necessarily a force, but a consequence of the curvature of space time that is caused by the uneven distribution of mass. But this could also be approximated by Newton's Law of Universal Motion. Gravity is a force acting upon two objects with masses at a certain amount of distance. So, the greater the mass, and the closer the objects are, the greater is the force of gravity. So, if you compare the gravity on Mars compared to Earth at a given distance, compare their masses. The mass of Earth is 5.972 × 10^24 kg while that of Mars is <span>6.39 × 10^23 kg. So, the gravity on Earth is much greater because Earth is heavier.

For the second question, let's base on Newton's Second Law of Motion which states: the force exerted on or by the object, is equal to its mass times acceleration. In equation, F = ma. So, if you want to increase acceleration, the force should be greater, while the mass should be lighter.</span>
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A stationary charge is located between the poles of a horseshoe magnet. Is a magnetic force excerted of the charge? why?
vredina [299]

A stationary charge is located between the poles of a horseshoe magnet. The magnetic force exerted by the charge is zero.

<h3>What is charge?</h3>

Charge is the physical property of matter which cause a particle to attract or repel when placed in its field.

A stationary charged particle does not interact with a static magnetic field. A charge placed in a magnetic field experiences a magnetic force. There will be no magnetic force acting on a stationary charge. The charge must be moving in order to have magnetic force on it.

Thus, the magnetic force exerted by the charge is zero.

Learn more about charge.

brainly.com/question/19886264

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7 0
2 years ago
14. A block rests on a frictionless table on Earth. After a 20-N horizontal force is applied to the block, it accelerates at 3.9
joja [24]
<span>14. Let's find mass. We know that F = m*a, so m = F/a.m = 20/3,9 m/s^2 = 5,12 kg;We already know the mass, so acceleration will be a = F/m;a = 10/5,12 = 2,0 m/s^2 (approximately);Answer: E.
15. According to the picture given above, let's define all components:These are refer to y: 985N sin(31)= 507;788N cos(32)= 668;411N sin(53)=-328;
And these are refer to x: 985N cos(31)= 844 788N sin(32)= -417 411N cos(53)= -247
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According to these calculations we've got: Sum Fx = 179,4 and Sum Fy = 847. Then let's count magnitude:Fsum = rad 179^2 + 847^2 = 865
Then we've got [tex]cos^-1 (179/865) = 77.7 (approximately).
So the most approximate answer is C. 866 N at 78.1° counterclockwise to the x-axis.
16. I think that this question is incomplete because there wasn't mentioned in what end of the chain the tension should be calculated. Anyway I'll help you with both bottom and top ends. We will use the basic formula W=m*g; W(bottom) = 175*9.8 = 1715 N; W(top) = (175+12)*9.8 = 1833 N; So you should choose between B. 1830 N or D. 1720 N. But I think the most possible answer is B.
17. I am definitely sure that A diagram generates the most tension in one chain. So the answer is C. The box is held by 1 chain and have all its weight.
18. I think that each planet would move in a straight line at constant speed, because there will be a zero gravity condition and there won't any impact on the planets.
19.  According to the Work-Energy Theorem we have:1/2*1200*2^2 = 2400 (J);Then let's count the average force according to the formula: Work =  F*D where D is displacement.F = 2400/ 0.15 = 16000 (N)
So the answer is B. 1.6 × 10^4 N
20. If my memory serves me well, magnetism is the force that can act through empty space. It's one aspect of the combined electromagnetic force. So the answer is A.
21. According to the illustration given above, I think we should use formula F = m*g; Let's count m. m = 5 kg - 0,6 kg = 4,4 kg; Then we have everything to count force:F = 4,4 * 9,8 = 43,1 N. So the most approximate answer is D. 43 N.
22. I am definitely sure that the answer is C. on Earth at sea level. Because weight has the formula W=mg. And on the earth surface the magnitude of g is higher that everywhere so the greatest weight is on Earth at sea level.
23. We have everything to calculate the acceleration. According to Newton's second law, the formula is a = F/m;a = 20/40 = 0,5 m/s^2; So the answer is A.
24. According to the definition of action reaction forces, the answer should be: A. The forces are opposite in direction, with the force on the ball much stronger in magnitude.
25. I am pretty sure that we should use Newton’s second law of motion F = m*a. First we should find mass, using formula W=m*g => m = W/g => m = 2400/9.8= 245 kg. Then we can find F.F = m*a;F = 245*12 = 2940 N; Answer: B
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7 0
3 years ago
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What is not an example of absorption ?
blsea [12.9K]

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3 years ago
You are driving at 35 m/s east and notice another car that is initially located 462 m in front of you and is moving east at 25 m
GaryK [48]

The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture.  Car 1 travels at 35m/s and Car 2 travels at 25m/s.  Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second.  So we can interpret Car 1's relative velocity to Car 2 as 10m/s.  Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.

v = 10m/s

d = 462m

v = d/t

(10) = (462)/t

t = 46.2s

So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up.  So we have to use Car 1's velocity and not the relative velocity:

v = 35m/s

v = d/t

(35) = d/(46.2)

d = 1617m

Car 1 traveled a total distance of 1617m.

7 0
4 years ago
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If the acceleration of a moving object is zero, which of the following best describes its motion
podryga [215]
If the acceleration of a moving object is zero, the object remains at a constant speed (without friction)
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