Compare and contrast properties of halogens in group 17 with the alkali metal family in group 1

Physics

1 answer:

N76 [4]3 years ago

7 0

Answer:

See the explanation below.

Explanation:

Halogens are compound of Group 17 of the periodic table. It's properties are:

Down the group the melting and boiling point of the elements increases, so, Fluorine will have the lowest whereas, Astatine will have the highest.
Down the group reactivity of halogens decreases, Fluorine reacts instantly whereas, iodine need to be heated strongly for reaction to take place.

Alkali metals are compound of Group 1 of the periodic table. It's properties include:

Alkali metal have low melting point and down the group melting point decreases i.e. Lithium have the melting point of 180 degree Celsius whereas, Cesium have the melting point of 28 degree Celsius only.
Down the group reactivity of these metal increases For example, Cesium reacts with Chlorine more vigorously as compare to reaction of Potassium with Chlorine.

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PLEASE HELP ME WITH THIS ONE QUESTION

Marizza181 [45]

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

<em>Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope</em>

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

<h3>c) 2.02 x 10^16 nuclei</h3>

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3 years ago

A plane is flying due east with the velocity of 90m/s. The wind is blowing out of the north at 4m/s. What is the magnitude of th

Butoxors [25]

<span> as we know that the velocity vectors are at right angles
magnitude = ?
hypotenuse of a right triangle.
v^2 = 90^2 + 4^2
v^2 = 8116
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v = 90.1 m/s
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3 years ago

2. A car accelerates uniformly from +10.0 m/s to +50.0 m/s over a distance of 225 m. How long did it take to go that distance? S

artcher [175]

Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

It took 7.5 seconds

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3 years ago

Solve for work when

BlackZzzverrR [31]

So, <u>the value of the work is approximately 84.65 J</u>.

<h2>Introduction</h2>

Hi ! Here I will help you to discuss the subject about work that caused by force in amount value of angle. Work is affected by the force and displacement.

If related to the magnitude of the force, the amount of work will be proportional to the magnitude of the applied force. Thats mean, if the value of the force that applied on it is greater, then the value of the work will be greater.
If related to the magnitude of shift, the amount of work will be proportional to the magnitude of shift of object. Thats mean, if the value of the shift on it is greater, then the value of the work will be greater.

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The work done by a moving object can be expressed in the equation:

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$\boxed{\sf{\bold{W = F \times s}}}$