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Marina CMI [18]
3 years ago
5

Compare and contrast properties of halogens in group 17 with the alkali metal family in group 1

Physics
1 answer:
N76 [4]3 years ago
7 0

Answer:

See the explanation below.

Explanation:

Halogens are compound of Group 17 of the periodic table. It's properties are:

  1. Down the group the melting and boiling point of the elements increases, so, Fluorine will have the lowest whereas, Astatine will have the highest.
  2. Down the group reactivity of halogens decreases, Fluorine reacts instantly whereas, iodine need to be heated strongly for reaction to take place.

Alkali metals are compound of Group 1 of the periodic table. It's properties include:

  1. Alkali metal have low melting point and down the group melting point decreases i.e. Lithium have the melting point of 180 degree Celsius whereas, Cesium have the melting point of 28 degree Celsius only.
  2. Down the group reactivity of these metal increases For example, Cesium reacts with Chlorine more vigorously as compare to reaction of Potassium with Chlorine.
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A nucleus splits to form two or more smaller nuclei during which process?
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nuclear fission

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All else equal, the payback period for a project will decrease whenever the_______.
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(B) cash inflows are moved earlier in time.

Explanation:

The payback period stated time-frame during which the initial amount of investment should be recovered. It is expressed in the year form

The formula to compute the payback period is shown below:

Payback period = Initial investment ÷ Net cash flow

where,  

The net cash flow = annual net operating income + depreciation expenses

The payback period of the project decreases when the accumulated starting year cash flows increases that results the movement of the cash inflows earlier in time

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What is true about energy that is added to a closed system?
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The correct answer is B

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Captain John Stapp is often referred to as the "fastest man on Earth." In the late 1940s and early 1950s, Stapp ran the U.S. Air
valentina_108 [34]

Answer:

The sled needed a distance of 92.22 m and a time of 1.40 s to stop.

Explanation:

The relationship between velocities and time is described by this equation: v_f=v_0+a*t, where v_f is the final velocity, v_0 is the initial velocity, a the acceleration, and t is the time during such acceleration is applied.

Solving the equation for the time, and applying to the case: t=\frac{v_f-v_0}{a}=\frac{0\frac{m}{s}-282\frac{m}{s}  }{-201\frac{m}{s^2} }=1.40s, where v_f=0\frac{m}{s} because the sled is totally stopped, v_0=282\frac{m}{s} is the velocity of the sled before braking and, a=-201\frac{m}{s^2} is negative because the deceleration applied by the brakes.

In the other hand, the equation that describes the distance in term of velocities and acceleration:x_f-x_0=v_0*t+\frac{1}{2}*a*t^2, where x_f-x_0 is the distance traveled, v_0 is the initial velocity, t the time of the process and, a is the acceleration of the process.

Then for this case the relationship becomes: x_f-x_0=282\frac{m}{s} *1.40s+\frac{1}{2}(-201\frac{m}{s})*(1.40s)^2=94.22m.

<u>Note that the acceleration is negative because is a braking process.</u>

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3 years ago
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1. thomas jefferson proposed using the length (l) of a simple pendulum whose period (t) was exactly 2 seconds as the definition
Alecsey [184]

The length of a 2 sec pendulum is 1 m.

Given that, initial length of the simple pendulum L₁ = 1 m

Initial time period T₁ = 2 sec

We need to find the length of the pendulum whose time period is 2 sec

T₂ = 2 sec

L₂ = ?

We know that the time period of the simple pendulum is given by the formula,

T = 2π√(L/g)

From the above relation, we can write T ∝ √L

T₁ / T₂ = √(L₁/L₂)

Making L₂ from the above relation, we have,

L₂ = (T₂² * L₁)/ T₁² = 2² * 1/ 2² = 1 m

Thus, the length of a 2 sec pendulum is 1 m.

To know more about time period:

brainly.com/question/17350379

#SPJ4

7 0
1 year ago
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