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Sergio [31]
3 years ago
6

An 11-year-old girl’s height increased by several inches in three months. Which example of the characteristics of life is most s

imilar?
A)An octopus camouflages with the ocean floor.
B)A giraffe eats leaves off a tree.
C)A bee stings a person who is swatting it away.
D)A kitten gains weight.
E)A butterfly moves pollen from one flower to another.

Physics
2 answers:
abruzzese [7]3 years ago
3 0
A kitten gains weight
Pie3 years ago
3 0

Answer:

D: A kitten gains weight.

Explanation:

You might be interested in
6. An article, which costs Rs. 850 is sold at a profit of 6%.
geniusboy [140]

Answer:

b) Rs.901  is the selling price

Explanation:

selling price = cost price+profit percentage/100 x cost price

cost price = 850

profit percentage = 6%

selling price = 850+6/100 x 850 = 901

soln 2

                              if 100 % = 850

therefore what about 106% = ?

106 x 805/100 = 901

ans = 901

if you need any clarification or more explanation pls do mention on the comment section.i would like to help more

Hope this helps and if it does mark as branliest answer thx

5 0
3 years ago
A ping pong ball with a dent in it can be put into a pan of boiling water. After a short amount of time, the dent will pop out.
kifflom [539]

heat from water goes into air in ball

air expands

ping goes the dent

6 0
3 years ago
Read 2 more answers
How do we know gravity is a field force?
Papessa [141]

Answer:

NOME  DEJACRESIBIR A QIU

Explanation:

7 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

W=-Fd

where

F is the magnitude of the frictional force

d = 38.0 m is the maximum displacement allowed for the truck

The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

F=\mu mg

where

\mu is the coefficient of kinetic friction between the truck and the lane

m is the mass of the truck

g is the acceleration of gravity

So we can rewrite the work done as

W=-\mu mg d (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

-\frac{1}{2}mu^2 = -\mu mg d

And solving for \mu, we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767

7 0
3 years ago
How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer:
zimovet [89]

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

W=\Delta K

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

K=\frac{1}{2}mv^2

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\  \\ \therefore K\approx532,346J \end{gathered}

Therefore, the answer is: 532,346 J.

5 0
1 year ago
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