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3 years ago

6

.Which of the following scenarios correctly describes Newton's First Law?

2 answers:

hodyreva [135]3 years ago

7 0

Answer:

A chair that for some reason won't move even after being pushed.

Explanation:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.

Hope this helps! Sorry if I'm wrong.

Dvinal [7]3 years ago

4 0

Answer:

Newton's 1st law of Motion: An object in motion tends to stay in motion. An object at rest tends to stay at rest unless acted on by a net force. If acted on my a net force, an object will accelerate.

Explanation:

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A diver rises quickly to the surface from a 5.0 m depth. If she did not exhale the gas from her lunds before rising, by what fac

Inessa [10]

Answer:

1.5 times

Explanation:

$h$ = depth of the diver initially = 5 m

$\rho$ = density of seawater = 1030 kg m⁻³

$P_{i}$ = Initial pressure at the depth

$P_{f}$ = final pressure after rising = 101325 Pa

Initial pressure at the depth is given as

$P_{i} = P_{f} + \rho gh\\P_{i} = 101325 + (1030) (9.8) (5)\\P_{i} = 151795 Pa$

$V_{i}$ = Initial volume at the depth

$V_{f}$ = Final volume after rising

Since the temperature remains constant, we have

$P_{f} V_{f} = P_{i} V_{i}\\(101325) V_{f} = (151795) V_{i}\\V_{f} = 1.5 V_{i}$

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3 years ago

What type of infant temperament is generally associated with better adjustment in adulthood?

Rashid [163]

Saying no and not throwing fits and manners.

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3 years ago

Which of the following is not a fluid?

Alinara [238K]

The choices are confusing. Air, oil, and alcohol are fluids at any reasonable temperature. Dry cement is not.

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3 years ago

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A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa

bearhunter [10]

Explanation:

Formula which holds true for a leans with radii $R_{1}$ and $R_{2}$ and index refraction n is given as follows.

$\frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

Since, the lens is immersed in liquid with index of refraction $n_{1}$ . Therefore, focal length obeys the following.

$\frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

and, $\frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}$

or, $f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}$

$f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}$

= 32.4 cm

Using thin lens equation, we will find the focal length as follows.

$\frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}$

Hence, image distance can be calculated as follows.

$\frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}$

$s_{i} = \frac{fs_{o}}{s_{o} - f}$

$s_{i} = \frac{32.4 \times 100}{100 - 32.4}$

= 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

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3 years ago

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