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irina [24]
3 years ago
7

the perimeter of a rectangle if the width is w centimeters and the length is 9 cm less than twice the width. write in algebraic

Mathematics
1 answer:
user100 [1]3 years ago
8 0

P= 2W+2L

L=2W-9

P=2W+2(2W-9)

P= 6W-18

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It would be a 90%. In the calculator 18 is what percent of 20.
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What number is 25℅ of 60
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The perimeter of a rectangle is about 13.9 cm. If you double the width of the rectangle the perimeter is about 17.8 cm. Find the
fredd [130]

Answer:

5cm by 1.95cm

Step-by-step explanation:

Let the length of the rectangle be x

Let the width be y

Perimeter of a rectangle = 2x + 2y

If the initial perimeter of a rectangle is about 13.9 cm, then;

13.9 = 2x + 2y ..... 1

If when the width is double the perimeter is 17.8cm, then;

17.8 = 2x + 4y ..... 2

Subtract 1 from 2;

13.9 - 17.8 = 2y - 4y

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y = 3.9/2

y = 1.95 cm

Substitute y = 1.95 into 1 to get x;

From 1;

13.9 = 2x + 2y

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13.9 = 2x + 3.9

2x = 13.9-3.9

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x = 5 cm

Hence the dimension of the smaller triangle is 5cm by 1.95cm

7 0
3 years ago
Edna earns $6 for each hour of yard work. How many hours in all will it take Edna to earn<br> $42?
madreJ [45]

Answer:

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Step-by-step explanation:

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I will give you 100 points HELp
Naddika [18.5K]

Answer:

CD ≈ 26.0 cm

Step-by-step explanation:

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BD × sin35° = 12 ( divide both sides by sin35° )

BD = \frac{12}{sin35} ≈ 20.92 cm

using the sine rule in Δ BCD

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CD × sin52° = 20.92 × sin102° ( divide both sides by sin52° )

CD = \frac{20.92sin102}{sin52} ≈ 26.0 cm ( to 3 significant figures )

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