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3 years ago

A plant that has a high amount of orange pigment carotene would have leaves what color?

Chemistry

1 answer:

coldgirl [10]3 years ago

7 0

The orange pigment carotene absorbs the orange wavelength of light very poorly, which makes the leaves appear orange.

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BRAINLIESTTT ASAP! PLEASE HELP ME :)

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3 years ago

What is the total number of atoms contained in 80 grams of neon?

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3 years ago

True or False: Photosynthesis can happen anytime, regardless of the amount of reactants present or the presence of sunlight.

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3 years ago

Read 2 more answers

The notation for a particular nucleus is r3785b. in an electrically neutral atom. How many electrons are in orbit about this nuc

Serhud [2]

$^{85}_{37}Rb$ has 37 electrons in the orbit about its nucleus.

<h3>How to write an atomic symbol with atomic mass and atomic number?</h3>

Atomic mass is the total number of neutrons and protons present in the nucleus of an element.

The atomic number is the total number of protons present in the nucleus of an element.

For writing an atomic symbol, atomic mass is written on the top left of the atomic symbol, and the atomic number is written on the downside of the left of the symbol.

$^{Atomic mass}_{Atomic number}X$

An electrically neutral atom is an atom that has an equal number of electrons as well as protons.

Thus from the above conclusion we can say that $^{85}_{37}Rb$ has 37 electrons.

Learn more about Atomic mass and atomic number here:

brainly.com/question/3187640

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2 years ago

Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi

bija089 [108]

<u>Answer:</u> The value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u> $B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b$

<u>Equation 2:</u> $H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}$

The net equation follows:

$B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c$

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=K_1\times K_2$

We are given:

$K_1=K_b$

$K_2=\frac{1}{K_w}$

Putting values in above equation, we get:

$K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}$

Hence, the value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

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3 years ago