The movement of a fluid during convection is a circular/oval motion since the fluid at the top sinks and the fluid at the bottom rises.
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Answer:
Entonces, velocidad instantánea = | v | = 0,25 m / s
Explanation:
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Solución
La velocidad instantánea está dada por,
v = dx / dt = pendiente de la curva x-t
aquí, del gráfico:
en x = 1 m ---> t = 8 s
en x = 3 m ---> t = 0 s
entonces, dx = 1-3 = -2 m
dt = 8-0 = 8 s
Entonces,
v = -2/8
v = -0,25 m / s
Dado que, pseed es una cantidad escalar.
Entonces, velocidad instantánea = | v | = 0,25 m / s
Answer:
A. The object falls a distance of 250 m
Explanation:
Hi there!
In the question, you have forgotten the acceleration due to gravity. However, looking on the web I´ve found a very similar problem in which the acceleration due to gravity was as twice as much as it is on Earth.
The equation of height of a falling object is the following:
y = y0 + v0 · t + 1/2 · g · t²
Where:
y = height of the object after a time t.
y0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (on Earth: ≅ -10 m/s² considering the upward direction as positive).
Let´s place the origin of the system of reference at the point where the object is released so that y0 = 0. Since the object falls from rest, v0 = 0.
Then, the height of the object after 5 s will be :
y = 1/2 · 2 · g · t² (notice that the acceleration due to gravity is 2 · g)
y = g · t²
y = -10 m/s² · (5 s)²
y = -250 m
The object falls a distance of 250 m.
To get it to start moving, he have to exert a force equal to its maximum force of static friction.
F= fs,max = Ms m g= (0.21) * (180) * (9.8) = 370 N
Let me know if im wrong but if not brainliest user for helping or best answer
