Answer:
acceleraions 5.76g and 20.55g
Explanation:
This constant acceleration exercise can be solved using the kinematic equations in one dimension
Vf = Vo + a t
As part of the rest Vo = 0
a = Vf / t
a = 282/5
a = 56.4 m / s2
In relation to the acceleration of gravity
a ’= a / g = 56.4 / 9.8
a ’= 5.76g
To calculate the acceleration to stop we use the same formula
a2 = 282 / 1.40
a2 = 201.4 m / s2
This acceleration of gravity acceleration function is
a2 ’= 201.4 / 9.8
a2 ’= 20.55g
D.) In order to calculate both of them, we must know the "FORCE" on the system.
An electric current will start to form when a part of the wire is within a magnetic field. Using the magnet you could put the whole wire into the magnetic field of the magnet and move it across the magnet so that a current starts to run.
Another way you could do it is to make the wire so that it looks like a coil and stick the magnet in the middle of the coil of wire. This will cause an induced current in the coil of wire.
