A sample of water with a mass of 587.00 kg is heated with 87 kJ of energy to a temperature of 518.4 K. The specific heat of wate

Question

3 years ago

12

r is 1 J-1 kg K-1. What is the initial temperature of the water?

2 answers:

Tems11 [23] · Answer 1 · 2021-12-26T06:02:21+03:00

7 0

The correct specific heat capacity of water is <em>4.187 kJ/(kg.K)</em>.

q = mCΔT

ΔT = q/mC = 87 kJ/[587.00 kg x 4.187 kJ/(kg.K)] = 87 kJ/(2547.8 kJ/K)

= 0.035 K

Ti = Tf - ΔT = 518.4 K - 0.0354 K = 518.365 K

uysha [10] · Answer 2 · 2021-12-26T07:19:26+03:00

uysha [10]3 years ago

7 0

Answer:

370.2 K

Explanation:

The explanation is in the attached image