a chemical property of iron is the ability to change it, hammer it, roll it, shape it etc
Answer:
in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution. (option C).
Explanation:
In a reaction where NaOH is added to H2O.
NaOH is considered a strong base, this means that in an aqueous solution ( in water) it's able to completely disassociate in ions.
There will not remain any NaOH in the solution. This means option D is not correct.
The ions in which NaOH will disassociate are : NaOH → Na+ + OH-
These ions we will find in the solution.
Not only Na+ because NaOH is a strong base, so there will be a lot of OH- ions as well in solution.
This means in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution.
Carbonation isn’t a force that causes such
Answer:
- 1. Dimensions: The sheet can be cut into several smaller pieces.
- 2. Shape: the sheet can be formed into a paper ball or any other shape (using origami for example).
- 3. Color: You can use crayons to paint the sheet and change its color.
Explanation:
<em>Physical changes</em> do not change the chemical properties. They do not transform the compounds that form the substances. They do not break and or form chemical bonds.
When you change the form, the state (solid, liquid or gas), the color, you are just changing physical properties.
Only chemical changes change the compounds that form the substance. For instance, if you burn the <em>sheet of paper</em>, then you are causing a chemical change because the organic matter in the paper will react with oxygen forming CO₂ and water, but by cutting, folding, smashing, or coloring with crayons, the compounds in the<em> sheet of paper</em> do not change.
Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q
To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.
[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.
The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.
To learn more about crystal field stabilization energy visit:brainly.com/question/29389010
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