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3 years ago

A glass blower can bend and shape a piece of glass that has been heated. Is glass a crystalline or an amorphous solid?

Chemistry

1 answer:

zavuch27 [327]3 years ago

5 0

it would be a crystalline solid, because it could be extended in multiple directions.

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0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K. When equilibrium is reache

HACTEHA [7]

Answer:

12.531 grams will be the final mass of calcium carbonate.

Explanation:

$CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)$

Partial pressure of carbon dioxide gas at equilibrium = $P=0.220 atm$

Volume of carbon dioxide gas = V = 10.0 L

Moles of carbon dioxide gas formed = n

Temperature of the gas = T = 385 K

$PV=nRT$ ( ideal gas equation)

$n=\frac{PV}{RT}=\frac{0.220 atm\times 10.0 L}{0.0821 atm L/mol K\times 385 K}=0.06960 mol$

According to reaction , 1 mole of carbon dioxide gas is formed from 1 mole of calcium carbonate,0.06960 mole of carbon dioxide gas will be obtained from :

$\frac{1}{1}\times 0.06960 mol=0.06960 mol$ calcium carbonate

Moles of calcium carbonate at equilibrium = 0.100 mol - 0.06960 mol = 0.03040 mol

After addition of 0.300 atm of carbon dioxide gas, more amount of calcium carbonate will be be formed.

Here, at the same temperature, the equilibrium pressure of the carbon dioxide gas is 0.220 atm so, entire 0.300 atm of carbon dioxide will get convert to calcium carbonate.

So amount moles of carbon dioxide gas added = moles of calcium carbonate formed after re-establishment of an equilibrium :

Partial pressure of carbon dioxide gas added at equilibrium = $P=0.300 atm$

Volume of carbon dioxide gas = V = 10.0 L

Moles of carbon dioxide gas formed = n

Temperature of the gas = T = 385 K

$PV=nRT$ ( ideal gas equation)

$n=\frac{PV}{RT}=\frac{0.300 atm\times 10.0 L}{0.0821 atm L/mol K\times 385 K}=0.09491 mol$

Moles of calcium carbonate = 0.09491 mol

Total moles of calcium carbonate in the container :

=0.03040 mol + 0.09491 mol = 0.12531 mol

Mass of 0.12531 moles of calcium carbonate :

0.12531 mol × 100 g/mol = 12.531 g

12.531 grams will be the final mass of calcium carbonate.

4 0

3 years ago

Which of the following is not a part of the carbon cycle

BabaBlast [244]

Condensation is NOT part of the carbon cycle

8 0

3 years ago

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1.50μm2. Convert this to square meters.

mash [69]

In scientific notation 1.5 square micrometers is 1.5e-12 square meters.

7 0

3 years ago

What is the maximum mass of sugar that could be dissolved in 1.3 l of water?

Alexeev081 [22]

Answer is: <span>the maximum mass of sugar that could be dissolved in 1.3 l of water in room temperature is 2652 grams.
</span><span>The solubility of sugar in water in room temperature is 204 g/100 ml.
Make proportion, if 204 grams of sugar dissolve in 100 ml of water, than how much dissolve in 1300 ml of water:
204 g : 100 ml = m(sugar) : 1300 ml.
m(sugar) = 204 g </span>· 1300 ml ÷ 100 ml.
m(sugar) = 2652 g ÷ 1000 g/kg = 2,652 kg.

6 0

3 years ago

Camphor is reduced to isoborneol by sodium borohydride in ethanol. The instructions for safe disposal of the chemical waste gene

Ronch [10]

Answer:

A) The reaction waste is still generating hydrogen gas that would get trapped in the container.

6 0

4 years ago

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