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3 years ago

The United Nations was founded primarily __________.

Physics

2 answers:

Margaret [11]3 years ago

9 0

<span>The United Nations was founded primarily B. to help international diplomacy</span>

Mekhanik [1.2K]3 years ago

8 0

Answer;

B. to help international diplomacy

Explanation;

The United Nations is an international organization founded in 1945 after the Second World War by 51 countries committed to maintaining international peace and security, developing friendly relations among nations and promoting social progress, better living standards and human rights.

The UN Charter sets out four main purposes: Maintaining worldwide peace and security. Developing relations among nations. Fostering cooperation between nations in order to solve economic, social, cultural, or humanitarian international problems.

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NEED HELP ASAP

bogdanovich [222]

The equation for gravity is given by:

$F_G = \frac{G m_1 m_2}{r^2}$

1. If r goes up by a factor of 3, gravity goes down by a factor of 9.
2. If m₁*m₂ goes up by a factor of 24, gravity goes up by a factor of 24.

5 0

3 years ago

An electron of kinetic energy 1.59 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 35.4 cm

Blizzard [7]

Answer:

a) $v = 2.36 \cdot 10^{7} m/s$

b) $B = 3.80 \cdot 10^{-4} T$

c) $f = 1.06 \cdot 10^{7} Hz$

d) $T = 9.43 \cdot 10^{-8} s$

Explanation:

a) We can find the electron's speed by knowing the kinetic energy:

$K = \frac{1}{2}mv^{2}$

Where:

K: is the kinetic energy = 1.59 keV

m: is the electron's mass = 9.11x10⁻³¹ kg

v: is the speed =?

$v = \sqrt{\frac{2K}{m}} = \sqrt{\frac{2*1.59 \cdot 10^{3} eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}}{9.11 \cdot 10^{-31} kg}} = 2.36 \cdot 10^{7} m/s$

b) The electron's speed can be found by using Lorentz's equation:

$F = q(v\times B) = qvBsin(\theta)$ (1)

Where:

F: is the magnetic force

q: is the electron's charge = 1.6x10⁻¹⁹ C

θ: is the angle between the speed of the electron and the magnetic field = 90°

The magnetic force is also equal to:

$F = ma_{c} = m\frac{v^{2}}{r}$ (2)

By equating equation (2) with (1) and by solving for B, we have:

$B = \frac{mv}{rq} = \frac{9.11 \cdot 10^{-31} kg*2.36 \cdot 10^{7} m/s}{0.354 m*1.6 \cdot 10^{-19} C} = 3.80 \cdot 10^{-4} T$

c) The circling frequency is:

$f = \frac{1}{T} = \frac{\omega}{2\pi} = \frac{v}{2\pi r}$

Where:

T: is the period = 2π/ω

ω: is the angular speed = v/r

$f = \frac{v}{2\pi r} = \frac{2.36 \cdot 10^{7} m/s}{2\pi*0.354 m} = 1.06 \cdot 10^{7} Hz$

d) The period of the motion is:

$T = \frac{1}{f} = \frac{1}{1.06 \cdot 10^{7} Hz} = 9.43 \cdot 10^{-8} s$

I hope it helps you!

8 0

3 years ago

A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?

maria [59]

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the mass in kg

v is the velocity in m/s

From the question

m = 60 kg

v = 10 m/s

We have

$k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000$

We have the final answer as

Hope this helps you

6 0

3 years ago

Read 2 more answers

Value of g is independent of

Margaret [11]

The lord of the greeks answer d

5 0

3 years ago

Read 2 more answers

If you weigh 660 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an

Arada [10]

Answer:

8.93*10^13 N.

Explanation:

Assuming that in this case, the weight is just the the force exerted on you by the mass of the star, due to gravity, we can apply the Universal Law of Gravitation:

$F_{g}= \frac{G*m_{1}*m_{s}}{r_{s}^{2} }$

where, m1 = mass of the man = 660 N / 9.81 m/s^2 = 67.3 kg, ms = mass of the star = 1.99*10^30 kg, G= Universal Constant of Gravitation, and rs= radius of the star = 10.0 km. = 10^4 m.
Replacing by the values, we get:

$F_{g}= \frac{6.67e-11Nm^2/kg^2*1.99e30 kg*67.3 kg}{10e4m^2} = 8.93e13 N$

Fg = 8.93*10^13 N.

6 0

3 years ago