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3 years ago

Which statement is true about planets with longer orbits in the solar system?

Physics

2 answers:

Yakvenalex [24]3 years ago

5 0

Answer:

D They have longer seasons

Explanation:

I think this because the days will be longer so that means that the seasons will change also.

Liula [17]3 years ago

3 0

Answer:

A.They have longer periods of revolution.

Explanation:

From Kepler's law, we understand that:

The planets revolve about the Sun in elliptical paths with Sun at one foci.
Equal areas is swiped in equal interval of time.
Closer the planet, faster it moves.

Thus, planets which have longer orbits that is are farther from the Sun have longer periods of revolution. This can be directly inferred from Kepler's third law.

P² ∝ a³

where, <em>P</em> is the period and <em>a </em>is the semi-major axis.

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The symbol for speed is v and the symbol for time is t. If v = 13t + 11, then what is t?

KonstantinChe [14]

't' is (v - 11) / 13 .

8 0

4 years ago

A rifle with a weight of 25 N fires a 4.0 g bullet with a speed of 290 m/s.

Ugo [173]

Answer:

Explanation:

Given

Weight of rifle $W=25\ N$

mass of rifle $M=\frac{25}{10}=2.5\ kg$

mass of bullet $m=4\ gm$

speed of bullet $u=290\ m/s$

As there is no net force on the bullet-rifle system therefore momentum is conserved

$0=Mv+mu$

$v=-\frac{mu}{M}$

$v=-\frac{4\times 10^{-3}\times 290}{2.5}$

$v=-0.464\ m/s$

i.e. opposite to the direction of bullet speed

(b)Weight of Man $=750\ N$

Combined weight of man and rifle $=750+25=775\ N$

mass of man-rifle system $M'=\frac{775}{10}=77.5\ kg$

Now man and rifle combinedly recoil

therefore

$0=(M')v '+mu$

$v'=-\frac{mu}{M'}$

$v'=-\frac{4\times 10^{-3}\times 290}{77.5}$

$v'=0.0149\ m/s$

3 0

4 years ago

Which of the following terms relate to the meaning of "physical"?

zubka84 [21]

Body is definitely one of them

7 0

4 years ago

Read 2 more answers

A ball is thrown horizontally from the top of

sesenic [268]

Answer:

42.5 m/s

Explanation:

Given:

x₀ = 0 m

x = 62 m

y₀ = 80 m

y = 0 m

v₀ᵧ = 0 m/s

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

Find: v

First, find the time it takes to land.

y = y₀ + v₀ᵧ t + ½ aᵧ t²

(0 m) = (80 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 4.04 s

Find the horizontal component vₓ:

x = x₀ + vₓ t − ½ aₓ t²

(62 m) = (0 m) + vₓ (4.04 s) − ½ (0 m/s²) (4.04 s)²

vₓ = 15.3 m/s

Find the vertical component vᵧ:

vᵧ = aᵧ t + v₀ᵧ

vᵧ = (-9.8 m/s²) (4.04 s) + (0 m/s)

vᵧ = -39.6 m/s

Find the speed using Pythagorean theorem:

v = √(vₓ² + vᵧ²)

v = √((15.3 m/s)² + (-39.6)²)

v = 42.5 m/s

3 0

3 years ago

A body is under the action of two forces 7N and 10N. Find the resultant of the two forces if the forces are parallel and act in

snow_lady [41]

Answer:K;O9KGVB

Explanation:

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3 years ago