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igor_vitrenko [27]
3 years ago
11

The SI unit for force is the newton. Which of the following is equivalent to a newton? A. kg/m B. kg·m/s2 C. kg·m/s D. kg·m/s

Physics
2 answers:
bearhunter [10]3 years ago
8 0
I may be wrong but A
Bad White [126]3 years ago
6 0

<u>Answer:</u> The unit of force, newton is equivalent to kg.m/s^2

<u>Explanation:</u>

Force is defined as the push or pull on an object with some mass that causes change in its velocity.  It is also defined as the mass multiplied by the acceleration of the object. The S.I unit of force is Newton.

Mathematically,

F=m\times a

The S.I unit of mass is kilograms

The S.I unit of acceleration is m/s^2  (meters per second square)

So, the unit of force becomes: kg.m/s^2

Hence, the unit of force, newton is equivalent to kg.m/s^2

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During a circus performance, a 72-kg humancannonball is shot out of an 18-m-long cannon. If thehuman cannonball spends 0.95 s in
andreyandreev [35.5K]

Answer:

2872.8 N

Explanation:

We have the following information

m =n72kg

Δy = 18m

t = 0.95s.

From here we use the equation

Δy=1/2at2 in order to solve for the acceleration.

So a

=( 2x 18m)/(0.95s²)

= 36/0.9025

= 39.9m/s2.

From there we use the equation

F = ma

F=(72kg) x (39.9)

= 2872.8N.

2872.8N is the average net force exerted on him in the barrel of the cannon.

Thank you!

7 0
2 years ago
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
RideAnS [48]

Answer:

Explanation:

Initial kinetic energy of M = 1/2 M vi²

let final velocity be vf

v² = u² + 2a s

vf² =  vi² + 2 (F / M) x D

Kinetic energy

= 1/2 Mvf²

= 1/2 M ( vi² + 2 (F / M) x D

1/2 M vi² + FD

Ratio with initial value

1/2 M  vi² + FD) / 1/2 M  vi²

RK = 1 + FD / 2 M  vi²

4 0
3 years ago
Using clay electric rates, how much does it cost to watch Netflix for 4 hours on a smart tv?
OverLord2011 [107]

Answer: TVs cost between $0.0015 and $0.0176

Explanation:

7 0
2 years ago
The overhang beam is subjected to the uniform distributed load having an intensity of w = 50 kn/m. determine the maximum shear s
alex41 [277]
Given:

Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.

We need to determine the maximum shear stress developed in the beam:

τ = F/A

Assuming the area of the beam is 100 m^2 with a length of 10 m.

τ = F/A
τ = W/l
τ = 50kN/m / 10 m
τ = 5kN/m^2
τ = 5000 N/ m^2<span />
8 0
3 years ago
What is the distance of separation between objects of masses 5.6 x 10 5 kg and 8.8 x 10 6 kg if the force of gravity between the
AlladinOne [14]

Answer:

2.87m

Explanation:

Using the law of gravitation to solve this question

F = GMm/r²

G is the gravitational constant

M and m are the masses

r is the distance between the masses

Substitute the given values

G = 6.67×10^-11 m³/kgs²

M =8.8 x 10^6 kg

m = 5.6 x 10^5 kg

F =440N

400 = 6.67×10^-11×8.8 x 10^6 ×5.6 x 10^5/r²

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r² = 3286.98/400

r² = 8.21745

r = √8.21745

r = 2.87m

Hence the distance of separation is 2.87m

7 0
3 years ago
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