<span>3 protons x 1.0073amu = 3.022 </span>
<span>4 neutrons x 1.0087amu = 4.035 </span>
<span>mass = 7.0567amu </span>
<span>mass defect = 7.0567 - 7.0144 = 0.0423amu.....B with your mass of Li</span>
Answer:
a) F = 680 N, b) W = 215 .4 J
, c) F = 1278.4 N
Explanation:
a) Hooke's law is
F = k x
To find the displacement (x) let's use the elastic energy equation
= ½ k x²
k = 2 / x²
k = 2 85.0 / 0.250²
k = 2720 N / m
We replace and look for elastic force
F = 2720 0.250
F = 680 N
b) The definition of work is
W = ΔEm
W = -
W = ½ k ( ² - x₀²)
The final distance
= 0.250 +0.220
= 0.4750 m
We calculate the work
W = ½ 2720 (0.47² - 0.25²)
W = 215 .4 J
We calculate the strength
F = k
F = 2720 0.470
F = 1278.4 N
Answer:
Four times higher
Explanation:
F- G (m1 x m2)/ r^2
if r 1 = 2 and r 2 = 1 therefore F = G (m1 x m2)/ 1^2 is 4 times higher than
2^2 since G and m1 and m2 remained the same
In a longitudinal wave, the motion of the medium is parrellel to the direction of the wave.