Answer:
The planes’ acceleration from A to B is 500m/s^2
Explanation:
Given that the initial velocity u is 8000m/s
and also given the final velocity v=10,000 m/s
the time taken to move from A to B = 40 second
The acceleration is defined as the rate of change of velocity with time
we know that the expression for acceleration is given as
a=(v-u)/t
substituting our given data into the expression for a we have
a=(10000-8000)/40
a=2000/40
a=500m/s^2
The planes’ acceleration from A to B is 500m/s^2
Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees
Answer:
more than
Explanation:
In a nuclear fusion reaction, the mass of the products is more than the mass of the reactants.
D. They are heterotrophs that digest food internally.
Answer:
k = 40 N/m
Explanation:
A spring's energy is given:
![U = 0.5kx^2](https://tex.z-dn.net/?f=U%20%3D%200.5kx%5E2)
U is the energy in the spring, k is the spring constant and x is the spring displacement.
We are told that the spring stores 5J of energy, therefore, U = 5J. We are also told that the spring is compressed by 0.5m, so the spring x = 0.5m
![5 J = 0.5k(0.5m)^2\\5J = 0.5k(0.25m^2)\\5J = k*(0.125)m^2\\\\k = 5J/(0.125)m^2\\k = 40 N/m](https://tex.z-dn.net/?f=5%20J%20%3D%200.5k%280.5m%29%5E2%5C%5C5J%20%3D%200.5k%280.25m%5E2%29%5C%5C5J%20%3D%20k%2A%280.125%29m%5E2%5C%5C%5C%5Ck%20%3D%205J%2F%280.125%29m%5E2%5C%5Ck%20%3D%2040%20N%2Fm)
k = 40 N/m
Hope this helps!